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Diano4ka-milaya [45]
3 years ago
10

DOES ANYONE KNOW IMAGINE MATH????? Please help ASAP would be HELPFUL!!! Thannks!!!!!!!!!!

Mathematics
2 answers:
Kazeer [188]3 years ago
8 0
Post the problem directly in the question, thanks
EleoNora [17]3 years ago
5 0

I am happy to help you with this if you need it. Also, brainliest would be appreciated. Thanks!

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What is the relationship between percents and decimals
Marizza181 [45]
Decimals and percentages are both systems of designating parts of a whole. 25% of an object is the same as 1/4 of an object which is the same as .25 of an object.
7 0
4 years ago
Kate made 4 dresses with 7 yards of fabric. how many yards did she use on 1 dress
Ksju [112]
This is a fraction equal to
7 yards ÷ 4 dresses

We want a unit rate where
<span>1 is in the denominator, </span>
so we divide top and bottom by 4.

7÷4= 1.75
_
4÷4=1.
Therefore, Kate used 1.75 yards per one dress (1.75 yds. p/ d)

Hope I helped! :)

5 0
3 years ago
HELP PLS ANSWER ASAP DUE TOMARROW
damaskus [11]

Answer:

they need to sell 15,000 because 42 percent of 15,00 is 6,300+2500=800

the inequality should be. 2500+0.42s≥8,800

and the number line should have a closed point on 15,000 with the line pointing to the right

6 0
3 years ago
Triangle ABC contains the point A(5,2). Find the coordinates of A' after a reflection over the x-axis
Sholpan [36]

Answer:

Step-by-step explanation:

Should be 5,-2 OR NOT

4 0
4 years ago
You coach a basketball ball team of 12 players; 5 players must be on the floor at all times; Figuring that every player can play
makvit [3.9K]
The function "choose k from n", nCk, is defined as
  nCk = n!/(k!*(n-k)!) . . . . . where "!" indicates the factorial

a) No position sensitivity.
The number of possibilities is the number of ways you can choose 5 players from a roster of 12.
  12C5 = 12*11*10*9*8/(5*4*3*2*1) = 792
You can put 792 different teams on the floor.

b) 1 of 2 centers, 2 of 5 guards, 2 of 5 forwards.
The number of possibilities is the product of the number of ways, for each position, you can choose the required number of players from those capable of playing the position.
  (2C1)*(5C2)*(5C2) = 2*10*10 = 200
You can put 200 different teams on the floor.
4 0
3 years ago
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