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Deffense [45]
4 years ago
9

8. 2²=1o=0z=+The solutions areand​

Mathematics
1 answer:
natka813 [3]4 years ago
8 0

Step-by-step explanation:

the question is z²=1

taking square root on both sides

√z² = √1

the square root and the square cancel out each other

it gives

z=±1

that means either z=+1 or z=-1

so the solutions are 1 and -1

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Answer:

197.77

Step-by-step explanation:

Area of circle: A=pi r^2

A= pi 9^2

A= 81 pi

only half of the circle so 40.5

Area of a Square: L x W

18 x 18 = 324

324 - 40.5pi = 197.77

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Plz explain properly if not i will report this and not put ANY RATINGS!!!!<br> so plz explain
Maurinko [17]

Answer:

The perimeter is 44cm.

Step-by-step explanation:

The perimeter is the length of all the sides. So, to calculate the perimeter, add all the sides together.

However, there are two sides that do not have a measure written. So we must first calculate them:

The long vertical side can be calculated by subtracting the other vertical sides by the long bottom side:

14 -  5 - 6 = 3cm

The missing horizontal side can be found by  subtracting the leftmost side by the shorter horizontal sides:

8 - 3 - 2 = 3cm

Now, add them all together:

8cm + 5cm + 3cm + 3cm + 3cm + 6cm + 2cm + 14cm = 44cm

6 0
2 years ago
Given the lists, lst1 and lst2, create a new sorted list consisting of all the elements of lst1 that also appears in lst2. For e
aalyn [17]

Answer:

lst1 = [4, 3, 2, 6, 2]

lst2 = [1, 2, 4]

new_lst =  []

for i in lst1:

      if i in lst2:

           new_lst.append(i)

new_lst.sort()

print(new_lst)

Step-by-step explanation:

The code is written in python.

lst1 = [4, 3, 2, 6, 2]

The variable lst1 represent a list of integers.

lst2 = [1, 2, 4]

The variable lst2 represent a list of integers.

new_lst =  []

An empty variable is created new_lst and it is used to store the values of lst1 that is in lst2.

for i in lst1:

The code loop through integers in lst1.

if i in lst2:

This code means if any of the value in lst1 is in lst2.

new_lst.append(i)

This code put the same values found in lst1 and lst2 in a new list(new_lst)

new_lst.sort()

We sort the value of the new list from the smallest to the biggest.

print(new_lst)

The new list is displayed

8 0
3 years ago
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