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FrozenT [24]
3 years ago
10

Use the unit circle to find the value of sin ³π/2 and cos ³π/2

Mathematics
2 answers:
VikaD [51]3 years ago
7 0

Answer:

SIn³ π/2 = 1³ = 1

cos³ π/2 = 0³ = 0

Step-by-step explanation:

Considering a circle of unit radius as shown in the image below.

So, OB = OA = 1 unit

Thus, by Pythagoras theorem,

OB² + OA² = AB²

So, AB² = 2

AB = √2 units

If ∠OAB = 90°

Then AB and OA approaches to OA. SO,

OB =  AB = 1 unit and OA = 0

Thus,

SIn π/2 = P/H = 1/1 = 1

Cos  π/2 = B/H = 0/1 = 0

So,

<u>SIn³ π/2 = 1³ = 1</u>

<u>cos³ π/2 = 0³ = 0</u>

juin [17]3 years ago
5 0

Answer:

1 and 0

Step-by-step explanation:

sin( \frac{\pi }{2} ) = 1, hence

sin³(\frac{\pi }{2} ) = 1³ = 1

cos( \frac{\pi }{2} ) = 0, hence

cos³ (\frac{\pi }{2} ) = 0³ = 0

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Write the equation of the line that passes through (-4,3) and is parallel to y = -2x - 8.
kobusy [5.1K]

Answer:

y = -2x - 5

Step-by-step explanation:

Let the equation if the line be y = mx + c

since the line is parallel to y = -2x - 8, their gradients/slope must be the same (aka m = -2)

sub (-4, 3):

3 = -2(-4) + c

c = -5

therefore, the equation of the line is y = -2x - 5

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2 years ago
What rational number represents this equation: 3+ (-0.5) - 3 1/4
olasank [31]

Answer:

A) -.75

Step-by-step explanation:

Used Symbolab.com to find the answer

3 0
3 years ago
This year, Mrs. Fisher has 9 students who are new to the school. The number of new students represents 7.5% of all her students.
Lelu [443]
7.5\% \text { of } x = 9 \text { students}

0.75 \times x = 9 \text { students}

0.75x = 9
5 0
2 years ago
Please I need help on this question, A line passes through (6,3), (8,4), and (n,-2). Find the value of n.
Vika [28.1K]

Answer:

n= -4

Step-by-step explanation:

First we have to find the equation of line which passes through (6,3) and (8,4).

Then we have to pass this line through the point (n , -2).

we know, equation of line passing through (x1,y1) and (x2,y2) is

\frac{x-x1}{x1-x2}=\frac{y-y1}{y1-y2}

So, the equation of line passing through (6,3) and (8,4) is

\frac{x-6}{6-8}=\frac{y-3}{3-4}

or, \frac{x-6}{-2} =\frac{y-3}{-1}

multiplying both sides by  -2

x-6=2(y-3)

or, x-6=2y-6

or, x-2y=6-6

or, x-2y=0


Now, we have to pass this line through  (n,-2)

So, using the point in the line, that is using  x=n  , y=-2

we get

n-2(-2)=0

or, n+4=0

or, n=-4

6 0
3 years ago
Read 2 more answers
A line segment is sometimes/always/never similar to another line segment, because we can sometimes/never/always map one into the
Fantom [35]

Answer:

A line segment is <u><em>always</em></u> similar to another line segment, because we can <u><em>always</em></u> map one into the other using only dilation a and rigid transformations

Step-by-step explanation:

we know that

A<u><em> dilation</em></u> is  a Non-Rigid Transformations that change the structure of our original object. For example, it can make our object bigger or smaller using scaling.

The dilation produce similar figures

In this case, it would be lengthening or shortening a line. We can dilate any line to get it to any desired length we want.

A <u><em>rigid transformation</em></u>, is a transformation that preserves distance and angles, it does not change the size or shape of the figure. Reflections, translations, rotations, and combinations of these three transformations are rigid transformations.

so

If we have two line segments XY and WZ,  then it is possible to use dilation and rigid transformations to map line segment XY to line segment WZ.

The first segment XY would map to the second segment WZ

therefore

A line segment is <u><em>always</em></u> similar to another line segment, because we can <u><em>always</em></u> map one into the other using only dilation a and rigid transformations

6 0
3 years ago
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