Complete question :
The development of AstroWorld ("The Amusement Park of the Future") on the outskirts of a city will increase the city's population at the rate given below in people/year t yr after the start of construction. 5,700√t + 11,000 The population before construction is 67,000. Determine the projected population 16 yr after the construction of the park has begun. people
Answer:
486,200
Step-by-step explanation:
Given that the rate of change in population is represented by the function:
f(t) = 5,700√t + 11,000
To get the original function, we take the integral of the rate function because the rate of change is obtained by taking the derivate of the original equation
f(t) = 5,700t^1/2 + 11,000
Taking the integral of f with respect to t:
∫(5,700t^1/2 + 11,000)
[5700t^(1/2 + 1)] / (1/2 + 1) + 11000t + C
[(5700t^3/2)/ 3/2] + 11000t + C
Where C = constant
If population before construction = 67000
Then C = 67000
t = time = 16 years
Substitute values into the original change equation:
[(5700(16)^3/2)/ 3/2] + 11000t + 67000
[(5700 * 64) / 1.5] + 11000(16) + 67000
243200 + 176000 + 67000
= 486,200
Answer:
y = -4x-4
Step-by-step explanation:
We need to find an equation of the line that passes through (1,0) and has a slope of m=-4.
The equation of a line is given by :
y = mx+c
Where
m is slope of line
Put all the values,
y = -4x+c
Put x = 1 and y = 0
So,
0 = -4(1)+c
c = -4
So, the required equation is :
y = -4x-4
There should be a graph there to show you and I think you plot it into the graph. I might be wrong
If i mean .913 then .91 but if u wrote it correctly then 900
Answer:
The 3rd option
Step-by-step explanation:
Look at the data provided:
12, 17, 18, 20, 16, 10, 13, 21, 9, 10, 22
In a box-and-whisker plot, draw a box from the first quartile to the third quartile:
Q1 = 11
Q3 = 19
A vertical line goes through the box at the median:
Median (Q2): 15
The whiskers go from each quartile to the minimum or maximum:
Minimum: 9
Maximum: 22
Hope this helped :)