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jekas [21]
4 years ago
11

A net of a square pyramid is shown below.

Mathematics
2 answers:
dimulka [17.4K]4 years ago
7 0
Since, you didn't upload the picture, I can only give you the steps to the problem. Then, you can find the correct answer.

To find the surface area of an object, you have to add up the areas of all the different faces. In a square pyramid, you have to find the area of the square base. Then, add it to the area of all the triangular sides.
Tasya [4]4 years ago
4 0

Answer:

No picture so i cannot answer the question but i can guide you to support.

Step-by-step explanation:

The way you would do a rectangle is: The area of a rectangle is A = l × w and the way you would do the triangle is The area of a triangle is A = one half × b × h...

Hope this helps...

:)  

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Explain why you can always use synethic division for dividing polynomials? (Will makr brainest!)
Oksana_A [137]

Answer:

somebody has answered this question on brainly

Step-by-step explanation:

brainly.com/question/2368242

brainly.com/question/12731430

3 0
3 years ago
A baseball is dropped from a glider 500 feet above the ground. The height (in feet) above the ground is modeled by the function
Sophie [7]

A) 436 ft

B) t = 5 sec

C) 5.60 s

Step-by-step explanation:

A)

The height of the ball at time t is given by the equation

h(t)=-16t^2+500

where

-16 ft/s^2 is the acceleration of the ball (acceleration of gravity, downward)

+500 is the initial height of the ball, at time t = 0

Here we want to find the height of the ball after 2 seconds, so at a time of

t = 2 s

Substituting into the equation, we find:

h(2)=-16\cdot 2^2+500=436 ft

B)

Here we want to find the time it takes for the ball to fall to a height of 100 feet above the ground, so the time t at which

h(t) = 100 ft

As stated in the text of the question, the height of the ball at time t is given by

h(t)=-16t^2+500

Since

h(t) = 100, we have

100=-16t^2+500

And solving for t we find:

16t^2=400\\t^2=25\\t=\pm 5

So, the correct solution is the positive one:

t = 5 sec

C)

The ball reaches the ground when the height of the ball has became zero:

h(t) = 0

The height of the ball at time t is given by

h(t)=-16t^2+500

And substituting

h(t) = 0

We get

0=-16t^2+500

And solving the equation for t, we find the time t at which the ball reaches the ground:

16t^2=500\\t^2=31.25\\t=\pm 5.6 s

So, the correct solution is the positive one:

t = 5.60 s

3 0
4 years ago
What is the value of 7^2 x 7^0
sineoko [7]
The answer is 49

Hope this helps
7 0
3 years ago
Read 2 more answers
4.07, 4.070, 4.70, 4.0700 what value is not equivalent.
larisa [96]
4.70, all the others can be simplified to 4.07 by taking away the zeroes after the 7 because they are not significant, The one before the 7 stays because it is significant as it is holding the tenths place value.
5 0
4 years ago
Read 2 more answers
I need help with this problem please! I'll add a picture of the problem with the answers.
GaryK [48]
Where is th epicture?
7 0
3 years ago
Read 2 more answers
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