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goldenfox [79]
4 years ago
12

25 POINTS!!!!

Mathematics
2 answers:
zhuklara [117]4 years ago
5 0

Answer:

The answer is -6 6/35, i just took the quiz and got it right.

Rom4ik [11]4 years ago
4 0
-6 6/35 ft. per minute is your answer
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Help!!! Will mark Brainliest!
AleksAgata [21]

Answer:

(x-5)² + y² = 4

Step-by-step explanation:

formula of circle: (x-h)² + (y-k)² = r²  where (h,k) is coordinate of center and r is radius

center: (5 , 0)    r = 2

Equation: (x-5)² + y² = 4

4 0
3 years ago
Help please :(??? I need an answer
Alecsey [184]

Answer:

C. $23 per day.

Step-by-step explanation:

The equation given is in slope-intercept form: y = mx + b, where m is the rate of change (slope).

In the given equation, m = 23, therefore, the rate of change is 23 units (in this case, dollars per day).

Hope this helps!

8 0
3 years ago
Assume you purchased a car for $2,300 and sold it one week later for $3,100. How much did your net worth change, if at all?
Natali5045456 [20]

Answer:

My net wroth would have changed by $800

Step-by-step explanation:

Because $3,100 - $2,300 = $800

4 0
4 years ago
-4x - 6y = 6<br> 4x + 6y = -4
Sloan [31]

Step-by-step explanation:

-4x - 6y = 6

4x + 6y = -4

To solve a system of equations, we can add the two equations and solve for one of the remaining variables -- let's try to eliminate the x variable when we add the two equations together.

Right now, there's a -4x term in the first equation, and a 4x term in the second equation, so if we add those together, we'll be able to eliminate the x variable altogether and solve for y.

However, when we also have a -6y term in the first equation and 6y term in the second equation, so adding these together will also eliminate the y term, leaving a 0 on the left-hand side of the equation.

If we add the two numbers on the right side of the equation, we get -2, which does not equal 0, meaning there are no solutions to this system of equations.

3 0
3 years ago
Read 2 more answers
If L=√(x^2+y^2), dx/dt =-4, dy/dt=3, find dL/dt when x=4 and y=3
yulyashka [42]

Hello,

L=\sqrt{x^2+y^2} \\\\\dfrac{dx}{dt}=-4\\\\\dfrac{dy}{dt}=3\\\\x=4, y=3\\\\\dfrac{\partial L} {\partial x} =\dfrac{x}{\sqrt{x^2+y^2}} \\\\\dfrac{\partial L} {\partial y} =\dfrac{y}{\sqrt{x^2+y^2}} \\\\\dfrac{dL}{dt} =\dfrac{\partial L} {\partial x}*\dfrac{dx}{dt}+\dfrac{\partial L} {\partial y}*\dfrac{dy}{dt}\\\\=-4*\frac{-4}{\sqrt{4^2+3^2}} +3*\frac{3}{\sqrt{4^2+3^2}}\\\\=\dfrac{16}{5} +\dfrac{9}{5} \\\\=5\\

5 0
3 years ago
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