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Leni [432]
3 years ago
6

The area of a square can be found using the equation A = s², where A is the area and s is the measure of one side of the square.

Mathematics
2 answers:
noname [10]3 years ago
5 0
The correct answer is B. s = √81 in. Hope I helped!
algol133 years ago
5 0

Answer: S=\sqrt{81} in.

Step-by-step explanation: <u><em>I did the test</em></u>

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calculate the total surface area and volume a cone of base diameter 14cm and height of 5 cm ( take pi= 22/7​
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4 0
3 years ago
In ΔQRS, s = 2.3 inches, ∠S=51° and ∠Q=44°. Find the area of ΔQRS, to the nearest 10th of an square inch.
postnew [5]

Answer:

Area of ΔQRS = 2.3 square inches

Step-by-step explanation:

From the given information,

<S + <Q + <R = 180^{o}

51 + 44 + <R = 180^{o}

95 + <R = 180^{o}

<R = 180^{o} - 95

    = 85^{o}

<R = 85^{o}

Applying the Sine rule, we have;

\frac{q}{SinQ} = \frac{r}{SinR} = \frac{s}{SinS}

Using \frac{r}{SinR} = \frac{s}{SinS}

\frac{r}{Sin 85} = \frac{2.3}{Sin51}

r = \frac{2.3*Sin85}{sin51}

  = 2.9483

r = 2.9 inches

Also, \frac{q}{SinQ} = \frac{s}{SinS}

\frac{q}{Sin44} = \frac{2.3}{Sin51}

q = \frac{2.3*Sin44}{Sin51}

  = 2.0559

q = 2.0 inches

From Herons formula,

Area of a triangle = \sqrt{s(s-q)(s-r)(s-s)}

s = \frac{2.3 + 2.0 + 2.9}{2}

  = 3.6

Area of ΔQRS = \sqrt{3.6(3.6-2.0(3.6-2.9)(3.6-2.3)}

                        = 2.2895

Area of ΔQRS = 2.3 square inches

8 0
3 years ago
Read 2 more answers
Find the product. (- d + 4)(- d - 4)
sashaice [31]
The product is
(-d)^2 -4^2 = d^2 -16 . . . . . corresponds to the 2nd selection
3 0
3 years ago
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