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Lady bird [3.3K]
3 years ago
13

Sara drove 96 miles on 3.2 gallons of gas. How many miles can Sara drive on 12.5 gallons of gas

Mathematics
2 answers:
jekas [21]3 years ago
7 0
375 miles 96 on 3.2 gallons of gas dived
Blababa [14]3 years ago
4 0

Answer:

375 miles

Step-by-step explanation:

Create a proportion where x is the number of miles she can drive on 12.5 gallons of gas:

\frac{96}{3.2} = \frac{x}{12.5}

Cross multiply and solve for x:

3.2x = 1200

x = 375

So, with 12.5 gallons of gas, Sara can drive 375 miles

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10. A manufacturer wanted to know if more coupons would be redeemed if they were mailed to the
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Using the t-distribution, it is found that the data does not provide convincing evidence that the mean number is greater when the coupons were addressed to a female.

<h3>What are the hypothesis tested?</h3>

At the null hypothesis, it is tested if there is no difference, that is, the mean is of 0, hence:

H_0: \mu = 0

At the alternative hypothesis, it is tested if the mean number is greater for females, that is, the mean is greater than 0, hence:

H_1: \mu > 0

<h3>What is the test statistic?</h3>

The test statistic is given by:

t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}

The parameters are:

  • \overline{x} is the sample mean.
  • \mu is the value tested at the null hypothesis.
  • s is the standard deviation of the sample.
  • n is the sample size.

In this problem, the parameters are given as follows:

\overline{x} = 1.5, \mu = 0, s = 4.75, n = 50.

Hence, the test statistic is given by:

t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}

t = \frac{1.5 - 0}{\frac{4.75}{\sqrt{50}}}

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Since the test statistic is less than the critical value for the right-tailed test, the data does not provide convincing evidence that the mean number is greater when the coupons were addressed to a female.

More can be learned about the t-distribution at brainly.com/question/26454209

5 0
2 years ago
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