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3 years ago

How to write 5.104 in word form

Mathematics

2 answers:

Phoenix [80]3 years ago

6 0

Five and one-hundred and four thousandths. Hope this helps

taurus [48]3 years ago

5 0

 . . five and one hundred four thousandths

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Will mark brainly nest if you know the answer and explanation Btw I'm a weeb you?

Irina18 [472]

I think... J because
x + 1 / x^3 - x
Factor out x from the expression
x + 1 / xx(x^2 - 1)
Use a^2 - b^2 = (a - b)(a + b) to factor the expression
x + 1 / x • (x - 1) • (x + 1)
Reduce the fraction with x+ 1
1 / x • (x - 1)
Distribute x through the parentheses
1 / x^2 - x
:)

5 0

3 years ago

What is the scale factor from polygon A to polygon B?

Arada [10]

You must divide the larger by the smaller... That will give you the scale factor.

For example: Rectangles 10 x 20 and 5 x 10

the scale factor us 10/5 = 20/10 = 2

Hope this helps.

4 0

2 years ago

How does the volume of an oblique cone change if the height is reduced to 2/3 of its original size and the radius is doubled

spayn [35]

The volume of oblique cone = $\frac{1}{3} \pi r^{2} h$

Now radius is doubled is now it is 2r

And height is reduced to 2/3 of its original size that is 2/3 h

So plugging the values we get volume

New Volume = $\frac{1}{3} \pi (2r)^2 (\frac{2}{3} h)$

= $\frac{1}{3} \pi 4r^2 (\frac{2}{3} h) = \frac{8}{6} \pi r^{2} h =\frac{8}{2} (\frac{1}{3} \pi r^{2} h )$ $=4*(\frac{1}{3} \pi r^{2} h )$

It means the volume becomes 4 times

3 0

3 years ago

Given: AB || DE , AD bisects BE. Prove: ABC = DEC using the ASA postulate.

Ket [755]

Answer:

As per ASA postulate, the two triangles are congruent.

Step-by-step explanation:

We are given two triangles:

$\triangle ABC$ and $\triangle DEC$ .

AD bisects BE.

AB || DE.

Let us have a look at two properties.

1. When two lines are parallel and a line intersects both of them, then alternate angles are equal.

i.e. AB || ED and $\angle B$ and $\angle E$ are alternate angles $\Rightarrow$ $\angle B = \angle E$ .

2. When two lines are cutting each other, angles formed at the crossing of two, are known as Vertically opposite angles and they are are equal.

$\Rightarrow \angle ACB = \angle DCE$

Also, it is given that AD bisects BE.

i.e. EC = CB

1. $\angle B = \angle E$

2. EC = CB

3. $\angle ACB = \angle DCE$

So, we can in see that in $\triangle ABC$ and $\triangle DEC$ , two angles are equal and side between them is also equal to each other.

Hence, proved that $\triangle ABC$ $\cong$ $\triangle DEC$ .

8 0

2 years ago

PLEASE HELP THIS IS VERY IMPORTANT I WILL GIVE YOU BRAIN THING IF ITS CORRECT (you can use a calculator if you want) <3

Ilia_Sergeevich [38]

Answer:

A. Diego's answer is not correct.

B. 0.00375

Step-by-step explanation:

a. As I counted the thickness of the paper I realized that 0.015 inches is way too think because if we stacked 500 of those it would be 7.5 inches tall.

b. 1.875 ÷ 500 = 0.00375. so that is your answer

5 0

2 years ago

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