Answer:
Step-by-step explanation:
Problem:
The possible values of x in the equation (60)x = 1;
Solution:
Such a problem like this in which the highest power of the unknown is 1 will have just one solution.
60x = 1
To solve this, we take the multiplicative inverse of 60;
the multiplicative inverse of 60 =
Use this inverse to multiply both sides of the expression;
60x = 1 x
x =
7 days a week
4x7=28
About 4 weeks each month
28x4=112
The answer should be 112 hours. I hope this helped
Suppose that some value, c, is a point of a local minimum point.
The theorem states that if a function f is differentiable at a point c of local extremum, then f'(c) = 0.
This implies that the function f is continuous over the given interval. So there must be some value h such that f(c + h) - f(c) >= 0, where h is some infinitesimally small quantity.
As h approaches 0 from the negative side, then:
As h approaches 0 from the positive side, then:
Thus, f'(c) = 0
A) 18
Apparently my answer has to be 20+ characters so this is filling space
