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3 years ago

The cost of 5 pounds of hamburger is $34. Which equation shows this in function notation?

Mathematics

2 answers:

Brut [27]3 years ago

7 0

According to the given statement,
It would be: Cost(5) = 34

In short, Your Answer would be Option D

Hope this helps!

podryga [215]3 years ago

4 0

This has to be 20 Characters long to tell you the answer, but the answer is A

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An ice cream shop offers 5 different types of ice cream, 6 different toppings and the option of having a small, medium or large.

prohojiy [21]

Answer:

90 possible outcomes.

Step-by-step explanation:

In order to find the total number of combinations possible you simply need to multiply the total number of each options with one another. For example, the number of options in each category are the following

types: 5

toppings: 6

size: 3 (small, medium, large)

Now we simply need to multiply all three of these numbers together to find the total number of possible outcomes.

5 * 6 * 3 = 90 possible outcomes.

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3 years ago

It takes Jimmy 11 minutes to sweep a porch.

lara31 [8.8K]

Like 6 minutes or somthin

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3 years ago

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Using the drawing, what is the vertex of angle 4? A. B B. C C. A D. D

fomenos

You cannot answer this question without a picture.

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3 years ago

Jane is making a suit which requires 2 5⁄8 yards for the jacket and 1 3⁄4 yards for the skirt. What's the total amount of materi

Amanda [17]

4 3/8 is what I believe to be the answer.<span />

4 0

4 years ago

What’s is the answer

kvasek [131]

When you are multiplying an exponent directly into a number/variable with an exponent, you multiply the exponents together.

For example:

$(x^{2} )^{3} = x^6$

$(x^{3} )^5=x^{15}$

When you are multiplying a variable with an exponent by another variable with an exponent, you add the exponents together.

For example:

$(x^{2} )(x^{3})=x^{5}$

$(x^{1} )(x^{2})=x^{3}$

$(\frac{(x^{-3})(y^{2})}{(x^{4})(y^{6})} )^{3}=\frac{(x^{-9})(y^{6})}{(x^{12})(y^{18})}$

You multiply 3 into each exponent in the numerator and the denominator

$\frac{(x^{-9})(y^{6})}{(x^{12})(y^{18})}= \frac{y^{6}}{(x^{9})(x^{12})(y^{18})}$

When you have a negative exponent, you move it to the other side of the fraction to make the exponent positive.

$\frac{y^{6}}{(x^{21})(y^{18})} = \frac{1}{(x^{21})(y^{12})}$

When you have something like this:

$\frac{x^{2}}{x^5}$

You subtract the exponents together, so:

$\frac{x^2}{x^5} = x^{2-5} = x^{-3} = \frac{1}{x^3}$

Your answer is the second option

3 0

3 years ago