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3 years ago

9

Jane is making a suit which requires 2 5⁄8 yards for the jacket and 1 3⁄4 yards for the skirt. What's the total amount of materi

al she needs?

1 answer:

Amanda [17]3 years ago

4 0

4 3/8 is what I believe to be the answer.<span />

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Decide whether each equation is true for all, one, or no values of x. -2x + 4 = -3x + 4

saul85 [17]

Answer:

It has no value.

Step-by-step explanation:

8 0

3 years ago

Point E is the midpoint of ab and point f is the midpoint of CD

Lorico [155]

AB is bisected by CD (TRUE). This is True because E is the midpoint between A and B and CD passes through E

CD is bisected by AB (FALSE) CD is bisected by point F and not AB

AE = 1/2 * AB (TRUE) since E is the midpoint of AB , E divides AB into two equal halves

EF = 1/2 * ED (FALSE) The true statement would have been CF = 1/2* CD

FD = EB (FALSE) sinc we do not know if CD and AB are of the same lengths

CE + EF = ED (TRUE) since F is the midpoint the sum of CE and EF is equal to ED

5 0

3 years ago

Read 2 more answers

Elevator is on the 16th floor. It goes up 12 floors, down 7 floors, up 3 floors, and then down 5

seropon [69]

Answer:

The elevator stops on the 19th floor.

Step-by-step explanation:

On the 16th floor, goes up 12 floors:

16 + 12 = 28

On the 28th floor, goes down 7 floors:

28 - 7 = 21

On the 21st floor, does up 3 floors:

21 + 3 = 24

On the 24th floor, goes down 5 floors:

24 - 5 = 19

6 0

3 years ago

the first group of students consists of 10 and their average age was 13 years old the next group consisted of 30 students and th

Kazeer [188]

Answer: The average was 9 years old find the average age of both groups is 10 years old.

Step-by-step explanation:

Formula foe average : $\text{Average} =\dfrac{\text{Sum of all observations}}{\text{Number of observations}}$

Given : The first group of students consists of 10 and their average age was 13 years old.

i.e. $13=\dfrac{\text{Sum of ages of students of first group}}{10}\\\\\Rightarrow\ \text{Sum of ages of students of first group}=13\times10=130$ (1)

The next group consisted of 30 students and their average was 9 years old.

i.e. $9=\dfrac{\text{Sum of ages of students of next group}}{30}\\\\\Rightarrow\ \text{Sum of ages of students of nextgroup}=9\times30=270$ (2)

Then from (1) and (2) , the sum of both groups (first group and next group )students = 130+270 =400

Combined students of both groups (first and next group )= 10+30=40

Now , the average of both groups = $\dfrac{\text{Sum of combined students}}{\text{combined students}}$

$=\dfrac{400}{40}=10$

Hence, the average was 9 years old find the average age of both groups is 10 years old.

4 0

3 years ago

Determine the coordinates of the intersection of the diagonals of parallelogram ABCD with vertices A(-4,6), B(5,6), C(4,-2), and

Dima020 [189]

This is the answer (0,2)

8 0

3 years ago