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alexira [117]
3 years ago
6

5 books with him, and he has 62 books to choose from. how many different ways can the books be selected?

Mathematics
2 answers:
Semenov [28]3 years ago
8 0
To choose 5 books out of 62
different ways are 62 c5
Artyom0805 [142]3 years ago
8 0
Answer: 6 471 002

Explanation:

\textnormal {Number of ways to choose} = \cfrac{62\times 61 \times 60\times 59\times 58 }{1\times 2 \times 3 \times 4 \times 5} = 6 471 002



The Wise Orange thinks that he should just take all the 62 books with him.
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How do i figure out these problems ?
Andreyy89

Given two vectors

v=(a,b),\quad w=(c,d)

they are parallel if they are a multiple of each other:

c=ka,\quad d=kb

You can easily test this by checking if

\dfrac{c}{a}=\dfrac{d}{b}

they are orthogonal if their dot product is null:

v\cdot w=ac+bd=0

For example, in the first case, we have

\dfrac{10}{3}\div 2 \neq \dfrac{4}{3}\div 5

So, they aren't parallel. Similarly, you have

2\cdot \dfrac{10}{3}+5\cdot \dfrac{4}{3}\neq 0

So, they aren't orthogonal.

In the second case, we have

\dfrac{5}{-12}\neq \dfrac{-6}{-10}

So, they aren't parallel, and

5(-12)+(-6)(-10)=-60+60=0

So, they are orthogonal.

Finally, we have

\dfrac{2}{-4}=\dfrac{-7}{14}=-\dfrac{1}{2}

So, they are parallel (and thus can't be orthogonal)

7 0
3 years ago
Suppose that X is a random variable with mean 30 and standard deviation 10. Also suppose that Y is a random variable with mean 2
Bas_tet [7]
Part a: For variable X using z score you have (x-30)/10, replace X for this expression in (a), i mean Z=2+10((x-30)/10) = 2+x-30= put this in the way of z score = (x-18)/1, so the mean is 18 and standard deviation is 1.
Part b: Z=X+Y= (x-30)/10 + (x-20)/8 = solve adding fractions = (18x-440)/80 now divide all the numbers between 18 (because you need to show as z score way) = (x-24.4)/4.4, so the mean is 24.4 and standard deviation is 4.4.
For part c,do the same.
3 0
3 years ago
Write the solution to the given inequality in the interval notation.
Sav [38]
The answer to this is (0,6).
4 0
4 years ago
Each of the 25 students in Mr. McDonald’s class sold 16 raffle tickets. If each ticket costs $15, how much money did Mr. McDonal
REY [17]
So do
25x16=400
this shows how many raffle tickets were sold all together
Then do 400x$15 =$6000
So all together they raised $6000
6 0
3 years ago
Read 2 more answers
PLEASE HELP!!!
Sholpan [36]
P=12T

Q=66T

-----------

Toys added to each bag:

P=12T+nT

Q=66T+nT

Therefore, 66T+nT=3(12T+nT)

------------

66T+nT=36T+3nT

T(66+n)=T(36+3n)

66+n=36+3n

3n-n=66-36

2n=30

Therefore, n=30/2=15

-------------

*She added 15 toys to each bag.
6 0
3 years ago
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