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alexira [117]
3 years ago
6

5 books with him, and he has 62 books to choose from. how many different ways can the books be selected?

Mathematics
2 answers:
Semenov [28]3 years ago
8 0
To choose 5 books out of 62
different ways are 62 c5
Artyom0805 [142]3 years ago
8 0
Answer: 6 471 002

Explanation:

\textnormal {Number of ways to choose} = \cfrac{62\times 61 \times 60\times 59\times 58 }{1\times 2 \times 3 \times 4 \times 5} = 6 471 002



The Wise Orange thinks that he should just take all the 62 books with him.
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Edgar Anderson earns $300 per week plus 15% commission on all sales over 1,000. if Mr. Anderson's sales for one week are 2,500 w
vredina [299]
Since he only makes commission on sales over $1000, he makes commission on $1500 (we find this by doing 2500-1000.) His commission is 15%, so find 15% of $1500:
.15*1500=225
So we know how makes $225 in commission.

Now we need to add this to his fixed pay to get his total pay:
225+300=525
So his total pay is $525, which is answer 'a' 

Hope I helped, and let me know if you have any questions :)
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4 years ago
Line segment TS is tangent to circle O at point N.  If the measure of QNT  is 74°, what is the measure of QPN?
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148         I just took the test.
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3 years ago
Read 2 more answers
Is 1 2/6 an irrational number
FrozenT [24]

Answer:yes

Step-by-step explanation:

7 0
3 years ago
a scout meeting lasts 2 hours. if 36 minutes was spent on making dream catchers, what percentage of the meeting is left
Llana [10]

Answer:

70% of the meeting is left.

Step-by-step explanation:

Hi, to answer this question, first, we have to convert the hours to minutes.

Since 1 hour = 60 minutes

For 2 hours:

1 /60 = 2/x

x = 2 (60)

x = 120 minutes

So, a scout meeting last 120 minutes (2 hours)

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120-36 = 84 minutes left

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8 0
4 years ago
Suppose a certain species of fawns between 1 and 5 months old have a body weight that is approximately normally distributed with
worty [1.4K]

Answer:

z

Step-by-step explanation:

Assuming this complete question:

"Suppose a certain species of fawns between 1 and 5 months old have a body weight that is approximately normally distributed with mean \mu =26 kilograms and standard deviation \sigma=4.2 kilograms. Let x be the weight of a fawn in kilograms. Convert the following z interval to a x interval.

X"

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:

X \sim N(26,4.2)  

Where \mu=26 and \sigma=4.2

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

We know that the Z scale and the normal distribution are equivalent since the Z scales is a linear transformation of the normal distribution.

We can convert the corresponding z score for x=42.6 like this:

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So then the corresponding z scale would be:

z

7 0
3 years ago
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