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strojnjashka [21]
3 years ago
10

NEED HELP IN MATH .THANKS

Mathematics
1 answer:
stira [4]3 years ago
6 0
It's simple. as long as it's a 10 you just put in however many 0 it has as the root to a 1. or just multiply it however many times.
10x10x10 = 1000
so 10^3 = 1000
then you finish
4.23 x 1000 = 4230
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The resulting equation after simplyfing the given equation is 3x^2 + 20x + 12 = 0 and whoose solutions are x = -2/3 or x = -6.

According to the given question.

We have an equation

\frac{x^{2}-x-6 }{x^{2} } = \frac{x-6}{2x} +\frac{2x+12}{x}

So, to find the resulting equation of the above equation we need to simplify.

First we will take LCD

\frac{x^{2} -x - 6 }{x^{2} } = \frac{x -6+2(2x + 12)}{2x}

\implies \frac{x^{2}-x-6 }{x^{2} } =\frac{x-6+4x+24}{2x}

\implies \frac{x^{2}-x-6 }{x^{2} } = \frac{5x +18}{2x}

Multiply both the sides by x.

\frac{x^{2}-x-6 }{x} = \frac{5x+18}{2}

Again multiply both the sides by x

2x^{2} -2x-12 = 5x^{2} +18x

\implies 5x^{2} -2x^{2} +18x +2x +12 = 0

\implies 3x^{2} + 18x+2x + 12 = 0

Factorize the above equation

⇒3x(x+6)+2(x+6) = 0

⇒(3x + 2)(x+6) = 0

⇒ x = -2/3 or x = -6

Hence, the resulting equation after simplyfing the given equation is 3x^2 + 20x + 12 = 0 and whoose solutions are x = -2/3 or x = -6.

Find out more information about equation here:

brainly.com/question/2976807

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