All categories

3 years ago

EFGH is a parallelogram. Find the measure of EG.

Mathematics

1 answer:

gayaneshka [121]3 years ago

7 0

Answer: 64

Step-by-step explanation:

If EFGH is a parallelogram, its diagonals bisect each other meaning EJ and JG are congruent.

EJ = JG

4w + 4 = 2w + 18

Subtract 2w from both sides

2w + 4 = 18

Subtract 4 from both sides

2w = 14

Divide both sides by 2

w = 7

EG = EJ + JG

EG = 4w + 4 + 2w + 18

EG = 6w + 22

Now that we know what 'w' is, we can substitute it for 7

EG = 6 (7) + 22

EG = 42 + 22 = 64

The measure of EG is 64.

Hope that helped!

You might be interested in

In ∆GHI and ∆JKL, GH = JK, HI = KL, GI = 9’, m∠H = 45°, and m∠K = 65°. Which of the following is not possible for JL: 5’, 9’ or

Aliun [14]

Answer:

hello

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

HELP PLEASE. BRAINIEST

Leona [35]

A
50 cents to 2.50 *I think I am not sure my sister has the same problem she said that one*

4 0

2 years ago

2. The population of Small Town, Alabama was 13,128 in 1990 but the town is growing at a rate

belka [17]

Answer i've done the math multiple times and everytime i get the answer 21,950. i don't think i'm doing the math wrong, maybe try asking the teacher or whoever is the one grading it cause it could be a typo or something like that.

Step-by-step explanation:

7 0

3 years ago

What is the slope of the tangent line to f(x)=-2+5 at x=4

Eddi Din [679]

Answer:

f'(4)=0

Step-by-step explanation:

6 0

2 years ago

The question is in the screenshot

Sidana [21]

Answer:

b. -36/77

Step-by-step explanation:

As 0 < x < $\pi$ /2 => tan x > 0

As 0< y < $\pi$ /2 => tan y > 0

We have the formula:

$\frac{1}{sin^{2}x } =1 + cot^{2}x$ => $\frac{1}{(8/17)^{2} }$ = $1+cot^{2}x$ => $cot^{2} x=225/64$

As tan x = 1/(cotx) => $tan^{2}x = \frac{1}{cot^{2}x} =\frac{1}{225/64} = \frac{64}{225}$

As tan x > 0 => tan x = 8/15

$\frac{1}{cos^{2}y } = 1+tan^{2}y$ => $\frac{1}{(3/5)^{2} } = 1 + tan^{2} y$ => $tan^{2}y=\frac{16}{9}$

As tan y > 0 => tan y = 4/3

As tan (x-y)= $\frac{tan x - tan y}{1+ tanx * tany}$ $=\frac{(8/15)-(4/3)}{1+(8/15)*(4/3)} = \frac{-36}{77}$

8 0

3 years ago