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damaskus [11]
3 years ago
13

3.Write the product as a trinomial. (2r – 5)(r + 10)

Mathematics
2 answers:
horrorfan [7]3 years ago
7 0
Use: (a + b)(c + d) = ac + ad + bc + bd

(2r-5)(r+10)=(2r)(r)+(2r)(10)+(-5)(r)+(-5)(10)=2r^2+20r-5r-50=2r^2+15r-50

Answer: b. 2r² + 15r - 50

Maurinko [17]3 years ago
5 0
B is the correct answer

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Question 14 Math Help please
Dmitry_Shevchenko [17]

ANSWER

(1,0) is a solution

EXPLANATION

The given inequality is

y \leqslant |x + 2|- 3

We substitute the point to see which ones satisfy the inequality.

For (1,0)

0\leqslant|1+ 2|- 3

0\leqslant 0

This is true.

(1,0) is a solution.

For (-1-1)

- 1\leqslant | - 1 + 2|-3

- 1\leqslant-2

False

(-1,-1) is not a solution.

For (0,0)

0\leqslant|0+2|-3

0\leqslant- 1

False.

For (0,1)

1\leqslant|0+ 2|-3

1\leqslant-1

This is also false

4 0
3 years ago
The sum of two times a number and 11 is negative 7
slavikrds [6]
|2 • x| + 11 = -7
x = -9
4 0
4 years ago
Read 2 more answers
How can you make the line of best fit for this picture?
BabaBlast [244]

Answer:

Step-by-step explanation:

(20,4), (100,22)

6 0
3 years ago
Suppose that 950 couples each have a baby find the mean and standard deviation for the number of boys in the 950 babies
nydimaria [60]

The mean and standard deviation for the number of boys in the 950 babies are 475 and 15.41, respectively

<h3>How to determine the mean and the standard deviation?</h3>

From the complete question, we have:

P(boy)= 0.5

Sample size = 950

The mean is then calculated as:

\bar x = np

This gives

\bar x = 950 * 0.5

Evaluate

\bar x = 475

The standard deviation is calculated as:

\sigma = \sqrt{np(1 - p)

This gives

\sigma = \sqrt{950 * 0.5(1 - 0.5)

Evaluate

\sigma = 15.41

Hence, the mean and standard deviation for the number of boys in the 950 babies are 475 and 15.41, respectively

Read more about mean and standard deviation at:

brainly.com/question/4079902

#SPJ1

4 0
2 years ago
Given that g(x)=x2, find each of the following.
nignag [31]

Step-by-step explanation:

a)

<u>g(3) = 9 </u>

b)

<u>g(-1) = 1</u>

c)

<u>g(-x) = x²</u>

d)

<u>g(2y) = 4y²</u>

e)

<u>g(1 + h) = 1 + h² + 2h</u>

<em>using</em><em> </em><em>the</em><em> </em><em>identity</em><em> </em><em>(</em><em>a</em><em> </em><em>+</em><em>b</em><em>)</em><em>²</em><em> </em><em>=</em><em> </em><em>a</em><em>²</em><em> </em><em>+</em><em> </em><em>b</em><em>²</em><em> </em><em>+</em><em> </em><em>2ab</em>

5 0
3 years ago
Read 2 more answers
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