Question

Suppose that 950 couples each have a baby find the mean and standard deviation for the number of boys in the 950 babies

Answer 1

The mean and standard deviation for the number of boys in the 950 babies are 475 and 15.41, respectively

How to determine the mean and the standard deviation?

From the complete question, we have:

P(boy)= 0.5

Sample size = 950

The mean is then calculated as:

$\bar x = np$

This gives

$\bar x = 950 * 0.5$

Evaluate

$\bar x = 475$

The standard deviation is calculated as:

$\sigma = \sqrt{np(1 - p)$

This gives

$\sigma = \sqrt{950 * 0.5(1 - 0.5)$

Evaluate

$\sigma = 15.41$

Hence, the mean and standard deviation for the number of boys in the 950 babies are 475 and 15.41, respectively

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