GCF(24, 30, 42) = 6 I think it is.
Answer:
True
Step-by-step explanation:
Answer:
Outside the circle
Step-by-step explanation:
Let's first write the equation of this circle:
, where (h, k) is the center and r is the radius. Here, the center is (-6, -2). We need to find the radius, which will just be the distance from N to E:
NE = ![\sqrt{(-6-(-1))^2+(-2-1)^2} =\sqrt{25+9} =\sqrt{34}](https://tex.z-dn.net/?f=%5Csqrt%7B%28-6-%28-1%29%29%5E2%2B%28-2-1%29%5E2%7D%20%3D%5Csqrt%7B25%2B9%7D%20%3D%5Csqrt%7B34%7D)
The radius is √34, which means that r² = 34. So, our equation is:
(x + 6)² + (y + 2)² = 34
Plug in -10 for x and -7 for y:
(x + 6)² + (y + 2)² = 34
x² + 12x + 36 + y² + 4y + 4 = 34
x² + 12x + y² + 4y + 40 = 34
x² + 12x + y² + 4y + 6 = 0
(-10)² + 12 * (-10) + (-7)² + 4 * (-7) + 6 = 7
Since 7 > 0, we know that H lies outside the circle.
Answer:
look at the photo..................
Answer:
x = 4
Step-by-step explanation:
6(x+3)-3= 39
6x+18-3 =39
6x+15 =39
-15 -15
6x= 24
/6 /6
x=4