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ira [324]
3 years ago
6

Yolanda wanted to buy a total of 6 pounds

Mathematics
1 answer:
Maslowich3 years ago
7 0

Answer:

No she didn't

Step-by-step explanation:

Add the total cost of the food and divide by 6. You'll find that she is short

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Jason and David went hiking at different times. Jason is currently 54 feet above sea level while David is starting at 11 feet be
tatuchka [14]
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3 0
3 years ago
What is the value of x in the equation 2(x+3) = 4(x-1)?<br> own
11111nata11111 [884]

Step-by-step explanation:

Solving

2x + 6 = 4x - 4

Bringing like terms on one side

6 + 4 = 4x - 2x

10 = 2x

10 / 2 = x

5 = x

8 0
3 years ago
A raft traveled 24 miles upstream on a river in 6 hours. The return trip took the raft 3 hours. What is the rate of the raft in
Lynna [10]

Answer:

                                                                   

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Confidence Interval Mistakes and Misunderstandings—Suppose that 500 randomly selected recent graduates of a university were as
kvv77 [185]

Answer:

The correct 95% confidence interval is (8.4, 8.8).

Step-by-step explanation:

The information provided is:

n=500\\\bar x=8.6\\\sigma=2.2

(a)

The (1 - <em>α</em>)% confidence interval for population mean (<em>μ</em>) is:

CI=\bar x\pm z_{\alpha/2}\times \frac{\sigma}{\sqrt{n}}

The 95% confidence interval for the average satisfaction score is computed as:

8.6 ± 1.96 (2.2)

This confidence interval is incorrect.

Because the critical value is multiplied directly by the standard deviation.

The correct interval is:

8.6\pm 1.96 (\frac{2.2}{\sqrt{500}})=8.6\pm 0.20=(8.4,\ 8.6)

(b)

The (1 - <em>α</em>)% confidence interval for the parameter implies that there is (1 - <em>α</em>)% confidence or certainty that the true parameter value is contained in the interval.

The 95% confidence interval for the mean rating, (8.4, 8.8) implies that the true there is a 95% confidence that the true parameter value is contained in this interval.

The mistake is that the student concluded that the sample mean is contained in between the interval. This is incorrect because the population is predicted to be contained in the interval.

(c)

The (1 - <em>α</em>)% confidence interval for population parameter implies that there is a (1 - <em>α</em>) probability that the true value of the parameter is included in the interval.

The 95% confidence interval for the mean rating, (8.4, 8.8) implies that the true mean satisfaction score is contained between 8.4 and 8.8 with probability 0.95 or 95%.

Thus, the students is not making any misinterpretation.

(d)

According to the Central Limit Theorem if we have a population with mean <em>μ</em> and standard deviation <em>σ</em> and we take appropriately huge random samples (<em>n</em> ≥ 30) from the population with replacement, then the distribution of the sample mean will be approximately normally distributed.

In this case the sample size is,

<em>n </em>= 500 > 30

Thus, a Normal distribution can be applied to approximate the distribution of the alumni ratings.

7 0
3 years ago
Here is a linear equation: y = 1/4x +5/4
docker41 [41]

Step-by-step explanation:

(1,1.5) is the solution but (12,4) is not the solution of given equation.

1.5=1/4×1+5/4(which is true)

4=1/4×12+5/4(which is false)

3 0
3 years ago
Read 2 more answers
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