Triangle QST is similar to triangle PQR
We are given that measure of angle SRP is 90°
Q is the point of the hypotenuse SP
Segment QR is perpendicular to PS and T is a point outside the triangle on the left of s
We need to find which triangle is similar to triangle PQR
So,
Using Angle - Angle - Angle Criterion We can say that
m∠PQR = m∠SQR (AAA similarity)
m∠SQR=m∠SQT (AAA similarity)
Where m∠Q =90° in ΔQST and PQR
Therefore ΔQST is similar to ΔPQR
Learn more about similarity of triangles here
brainly.com/question/24184322
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I am going to guess you want to find a line which passes through the points (0,4) and (2,10)...
y₂-y₁ / x₂-x₁
10 - 4 / 2 - 0
6 / 2
3....slope
(0,4) .....b
y = 3x + 4
Answer:
The length of AA' = √29 = 5.39
Step-by-step explanation:
* Lets revise how to find the length of a line joining between
any two points in the coordinates system
- If point A is (x1 , y1) and point B is (x2 , y2)
- The length of AB segment √[(x2 - x1)² + (y2 - y1)²]
* Lets use this rule to solve the problem
∵ Point A is (0 , 0)
∵ Point A' = (5 , 2)
∵ (x2 - x1)² = (5 - 0)² = 5² = 25
∵ (y2 - y1)² = (2 - 0)² = 2² = 4
∴ The length of AA' = √(25 + 4) = √29 = 5.39
Answer:
Step-by-step explanation:
Sin(A) = 5/7
Sin(A) = 0.7143
A = sin-1(0.7143
A = 45.58
B = 180 - 45.58 - 90
B = 44.43
C = 90
c = 7
a = 5
b^2 = c^2 - a^2
b^2 = 7^2 - 5^2
b^2 = 49 - 25
b^2 = 24
b = 4.899
