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Ksju [112]
3 years ago
7

How do u solve proportion equations

Mathematics
1 answer:
jok3333 [9.3K]3 years ago
7 0
You draw a line and then a = and another line on another side


like this but bigger ––=––
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16 more than s is at most −80.
polet [3.4K]

Answer:

s + 16 ≤ −80

Step-by-step explanation:

Analyze each part in the word equation:

"16 more than s"     s increased by 16; s + 16

"is at most"           is equal to or less than; ≤

"−80"               -80

Put the equation back together:

s + 16 ≤ −80

4 0
3 years ago
The stemplot below represents the number of bite-size
navik [9.2K]
Hey can someone help me with my latest question no one‘s helping me and I really need it
6 0
3 years ago
What is each number in scientific notation? Drag the answer into the box to match each number. 0.0000855 ?8.55×10?5? 855,000
Vera_Pavlovna [14]
I'm confused on what you're asking, but this is scientific notation on the first one of 0.0000855. 8.55 x 10^-5

7 0
3 years ago
Read 2 more answers
The legs of a 45-45-90 triangle have a length of eight units. What is the length of its hypotenuse?
Feliz [49]
The hypotenuse of a 45 45 90 triangle equals one of the legs times the square root of 2
hypotenuse = 8 * <span> <span> <span> 1.4142135624 </span> </span> </span>
hypotenuse = <span> <span> <span> 11.3137084990 </span> </span> </span>

Source:
http://www.1728.org/trig2.htm


6 0
3 years ago
Solve the system of equations by the addition method.<br> 1 - 3x = -5y - 8<br> 6x<br> 3y = -5
Advocard [28]

-3x = -5y -8~~~....(i) \\\\6x -3y = -5 ~~......(ii)\\\\\text{Multiply  equation (i) by 2 and do (i) + (ii):}\\\\2 \cdot (-3x) + 6x  -3y = 2(-5y-8)  + (-5)\\\\\implies -6x +6x -3y = -10y -16 -5 \\\\\implies -3y   = -10y -21\\\\\implies -3y +10y =-21\\\\\implies 7y = -21 \\\\\implies y = -\dfrac{21} 7 = -3\\\\\text{Substitute}~y =-3~ \text{in equation (ii):} \\\\6x - 3(-3) = -5\\\\\implies 6x +9  = -5\\\\\implies 6x = -5 -9 = -14\\\\\implies x = -\dfrac{14}6 = - \dfrac{7}3\\

\text{Hence}~ (x,y) = \left(-\dfrac 73, -3 \right)

3 0
2 years ago
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