Explaining the question, you want to find the x-value by setting up this equation.
(3x-28) + 90 + (66-x) = 180
(3x-28) and (66-x) - When you find x, inputting the actual numerical value of x will result in finding the degree of the angle the expression is in.
90 - 90 is the implied numerical degree behind a square in between two lines of an angle.
180 - 180 is the numerical degree implied behind a straight line in which you will find the expression on the left side of the equation will be equal to 180 once you find the x-value.
From here, you want to isolate the x by subtracting 90 from both sides.
(3x-28) + (66-x) = 90
Then you want to combine like terms.
2x + 38 = 90
You will receive this answer only because 28 is being SUBTRACTED from 3x just like x is being SUBTRACTED from 66. When an integer is being subtracted from another integer that integer can read as negative also. So when adding -28 to 66, or adding 3x to -x, in reality, you are subtracting 66 by 28 (66 - 28) and subtracting 3x by x (3x - x).
After this, you want to subtract 38 from both sides.
2x = 52
Divide 2x and 52 by 2 to isolate x since 2 is being MULTIPLIED by x.
x = 26
Then input 26 into the original equation to solve for 3x - 28.
3(26) - 28 = 50
Since you want to find the angle measure of <AOE, subtract 180 by 50 since <BOA and <AOE form line BE.
180 - 50 = 130
Then 130 is your answer.
