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igor_vitrenko [27]
3 years ago
6

POINTS! + WHOEVER ANSWERS BOTH CORRECTLY GETS TO BE THE BRAIN!!!!!!!!

Mathematics
2 answers:
Nitella [24]3 years ago
7 0
First off the answer to the problem is 3x^7 Multiply 3 3 by −7<span> - </span>7<span> to get −21 - 21 . Move all terms containing </span>x x<span> to the left side of the equation. Since 3</span>x<span> 3 ⁢ </span>x<span> contains the variable to </span>solve<span> for, move it to the left side of the equation by subtracting 3</span>x<span> 3 ⁢ </span>x<span> from both sides. Subtract 3</span>x<span> 3 ⁢ </span>x<span> from 3</span>x<span> 3 ⁢ </span>x<span>to get 0 0
hope it helped =)</span>
devlian [24]3 years ago
6 0
(ab)/(cd)=(a/c)(b/d)
and
(x^m)/(x^n)=x^(m-n)

so
(57x^5)/(19x^2)=(57/19)(x^5/x^2)=(3)(x^5-2)=3x^3




excluded values are the factors factored out

57/19=(19*3)/(19)
excluded value is 19

for
(x^5)/(x^2)=(x^2*x^3)/(x^2)
excluded value is x^3

so

excluded values are 19 and x^3

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What is the solution to this system of equations? 4x + 5y = 7
Nutka1998 [239]

Answer:

(-2, 3)

Step-by-step explanation:

4x + 5y = 7

3x - 2y = -12

Let's solve this by elimination. We want to eliminate one variable at a time. This means we need to multiply the equations to create a common multiple to cancel out a variable.

Let's work with y.

5y and -2y: For these values to cancel out, we need to multiply each term to create a common multiple.

2(4x + 5y = 7)

5(3x - 2y = -12)

Multiply.

8x + 10y = 14

15x - 10y = -60

Eliminate.

23x = -46

Divide both sides by 23.

x = -2

Now that we know x, let's plug it back into one of equations to find y.

4x + 5y = 7

4(-2) + 5y = 7

Multiply.

-8 + 5y = 7

Add.

5y = 15

Divide.

y = 3

Now we know x and y; let's plug both back into the equation we have not checked yet.

3x - 2y = -12

3(-2) - 2(3) = -12

Multiply.

-6 - 6 = -12

Subtract.

-12 = -12

Your solution is correct.

(-2, 3)

Hope this helps!

8 0
3 years ago
What is the domain and range of each relation?
LUCKY_DIMON [66]

Answer:

\text{Domain of}R_1=\{-2,0,2,4\}  and \text{Range of}R_1=\{-3,-1,0\}

\text{Domain of}R_2=\{-3,-1,0,3\}  and \text{Range of}R_2=\{-1,0,1,2,3\}

Step-by-step explanation:

Domain is the set of input values or x-values.

Range is the set of output values or y-values.

According to the relation mapping diagram, the relation is

R_1=\{(-2,-3),(-2,-1),(0,0),(2,0),(4,-3)\}

So,

\text{Domain of}R_1=\{-2,0,2,4\}

\text{Range of}R_1=\{-3,-1,0\}

In the graph 5 points are plotted. So, the relation is  

R_2=\{(-3,1),(-1,-1),(0,0),(3,2),(3,3)\}

So,

\text{Domain of}R_2=\{-3,-1,0,3\}

\text{Range of}R_2=\{-1,0,1,2,3\}

4 0
4 years ago
What is the value of 11g - 9k + 3 when g = 9 and k = 11?<br> Neatly show your work.
fenix001 [56]

Answer:

3

Step-by-step explanation:

11g - 9k + 3

Let g = 9 and k =11

11 * 9 - 9*11 +3

Multiply

99 - 99 +3

Add

3

4 0
3 years ago
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dezoksy [38]

Answer:

Y=x^2-2x-8

Step-by-step explanation:

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6 0
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