Answer:
Lines AB and A'B' are similar, line A'B' being three times the size of line AB. They would not be congruent since a dilation isn't a rigid transformation but they would be similar. Their lengths would also be expressed in the form of a ratio which would be 1:3 if you do AB to A'B' and 3:1 if you do A'B' to AB. Hope this helped! :)
Step-by-step explanation:
The relationship between two lines AB and A’B’ is A'B'=3AB.
It is given that in the given figure larger figure was dilated using a scale factor of 3. It means the smaller and larger figures are similar and there corresponding sides are in the ratio 1:3.
The line AB connecting the two points of the smaller figure and line A'B' connecting the two points of the larger figure.
Since A'B' is corresponding line segment of AB in larger figure, therefore the ratio of AB to A'B' is 1:3.
By cross multiplication we get
The length of segment A'B' is 3 times of AB.
MARK ME BRAINLIEST!
┏─━─━─━─━∞◆∞━─━─━─━─┓ ✭✮ӇЄƦЄ ƖƧ ƳƠƲƦ ƛƝƧƜЄƦ✮✭ ┗─━─━─━─━∞◆∞━─━─━─━─┛
➧ Which statement is true?
➫ [B] In any right triangle, the sine of one acute angle is equal to the sine of its complementary angle.
Mark Brainliest Please...❤
The answer is 90 degrees because 62+28=90 and the area of a triangle is 180 degrees so 180-90=90
For what shape? It depends on the shape
Answer:
x=4
y=-3
Step-by-step explanation:
use substitution method :
1)
7x + 8y = 4 ... (1)
3x + 2y = 6 ... (2)
2) Create the third equation by using
equation (2)
3x + 2y = 6
3x = 6-2y
x = 6-2y/3 ..... (3)
3) Substitute (3) into (1)
7(6-2y)/3 + 8y = 4
4) Solve the equation
42 - 14y /3 + 8y = 4
42 -14y+24y = 12
10y = 12-42
y = -3
5) Find value of x
x = 6-2y/3
= 6 -2(-3)/3
= 12/3
= 4
