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3 years ago

How do you write 80% as a fraction, mixed number, or whole number in simplest form?

2 answers:

7 0

For the fraction you start off by putting 80 over 100 and start simplifying which gives you 4/5 as for a mixed number or a whole number it isn't possible since it isn't a total whole. In order for you to have a mixed number you need something over a whole or something over a 100%

Anit [1.1K]3 years ago

6 0

A percent can be viewed as a fraction over 100, so in this case, we form the fraction 80/100.

However, this is not in simplest form. The largest number that goes into both of these (greatest common factor) is 20, so we should divide the numerator and denominator by 20.

When we do this, we can see that the simplest fraction to represent 80% is 4/5.

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For a standard normal distribution,Find P(-1.21 < Z< 2.26)

Mars2501 [29]

Answer:

The range of z-score is given below as

$P(-1.21Using a graphing calculator, we will have the image be[tex]\begin{gathered} P(z$

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1 year ago

Plz answer all corectly will mark brainlest plz answer within 1 hour

denis23 [38]

Answer:

for the first one I got y=-2x-2 the second part i got y=-x-1 or -1x-y-1=0 Correct me if I am wrong

Step-by-step explanation:

Use the slope formula

-4-4 =-8

/ =-2

1 - -3=4

2. The second part use this formula y-y1=m(x-x1)

y--4=-1(x-3)

y+4=-x+3

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y=-x-1 or -1x-y-1=0 I am not sure

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3 years ago

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zavuch27 [327]

Answer:

Step-by-step explanation:

3in/4 = 0.75in(Diameter) for each circle

r = 0.375

A = πr^2

A(for 1 circle) = 0.141π

A(for 1/4 circle) = 0.035π

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2 years ago

Read 2 more answers

15 players two coaches and 21 parents attend this year sports banquet the cost of each meal was $12 +5% sales tax what was the t

Artist 52 [7]

Answer:

$478.80

Step-by-step explanation:

We have been given that 15 players two coaches and 21 parents attend this year sports banquet the cost of each meal was $12 plus 5% sales tax.

First of all, we will find cost of each meal with tax as:

$\text{Cost of each meal with tax}=\$12+\$12\times \frac{5}{100}$

$\text{Cost of each meal with tax}=\$12+\$12\times 0.05$

$\text{Cost of each meal with tax}=\$12+\$0.6$

$\text{Cost of each meal with tax}=\$12.6$

Now, we will find total persons at the sport banquet as:

$\text{Total persons at banquet}=15+2+21$

$\text{Total persons at banquet}=38$

To find the total cost of food for the banquet, we will multiply cost of food for each person by 38.

$\text{Total cost of food for the banquet}=\$12.6\times 38$

$\text{Total cost of food for the banquet}=\$478.8$

Therefore, the total cost of food for the banquet is $478.80.

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3 years ago

An urn contains three red balls and four blue balls. Draw two balls at random from the urn, without replacement. Compute the exp

mezya [45]

Step-by-step explanation:

in total we have 3+4 = 7 balls.

when we draw the first ball, the probability to draw a red ball is 3/7, and a blue ball 4/7.

when we draw the second ball, we have now only 6 balls in total.

the probabilty to draw a red back now depends also on the result of the first draw.

if the first ball was already red, then we have only a chance now of 2 out of 6.

if the first ball was blue, then we have now a chance of 3 out of 6.

so, the probably to draw at least 1 red ball in 2 draws is the probability of drawing one on the first draw plus the probability of drawing one on the second :

1 - probability to see 2 blue balls

1 - 4/7 × 3/6 = 1 - 12/42 = 30/42 = 0.714285714...

the expected number of red balls in 2 draws is

1 red in first red in first red in second

but not second and second but not first

1×(3/7 × 4/6) + 2×(3/7 × 2/6) + 1×(4/7 × 3/6) = 12/42 + 12/42 + 12/42 = 36/42 = 6/7 = 0.857142857 ≈ 0.8571

7 0

2 years ago