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Marta_Voda [28]
4 years ago
5

it costs luis $5 to park his car at a parking meter for 2 hours. what is the price to park for 1 hour? write and solve an equati

on for this situation.
Mathematics
2 answers:
Sedbober [7]4 years ago
3 0
So I did 5/2 and I got 2.5
5 divided by 2 = 2.5
Not 100% sure if I'm right though
Neporo4naja [7]4 years ago
3 0
The equation can be:
5=2x (x is the number of hours)
If you divide both sides by 2 you get x=5/2 or 2.5

So the answer is $2.50 per hour
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Help please!!!! 10 points
Artemon [7]

Step-by-step explanation:

This is the answer.... Working shown

3 0
4 years ago
List the next four multiples of the unit fraction 1/5,
svetoff [14.1K]
Next multiples of the unit fraction 1/5 are
2/5
3/5
4/5
5/5 = 1

Hope this helps..  :)
6 0
3 years ago
HELP PLEASE. For parallelogram LMNO, if m∠L = 3x - 25 and m∠N = 2x - 10, find m∠M.
Dvinal [7]
In a parallelogram opposite angles are congruent, that means:

Angle L = Angle N, replace L & N by they respective value, then

3x-25 = 2x-10 ==> x=15 , Now plug the value of x in any of the 2 sides
3(15) -25 =20°

hence Angle L =- Angle N = 20°

Now let's calculate Angle M. In a parallelogram the adjacent angle are supplementary, that means their sum = 180°, then

Angle N + Angle N = 180°==> Angle M = 180°-20° = 160°
5 0
3 years ago
The plane x + y + z = 12 intersects paraboloid z = x^2 + y^2 in an ellipse.(a) Find the highest and the lowest points on the ell
emmasim [6.3K]

Answer:

a)

Highest (-3,-3)

Lowest (2,2)

b)

Farthest (-3,-3)

Closest (2,2)

Step-by-step explanation:

To solve this problem we will be using Lagrange multipliers.

a)

Let us find out first the restriction, which is the projection of the intersection on the XY-plane.

From x+y+z=12 we get z=12-x-y and replace this in the equation of the paraboloid:

\bf 12-x-y=x^2+y^2\Rightarrow x^2+y^2+x+y=12

completing the squares:

\bf x^2+y^2+x+y=12\Rightarrow (x+1/2)^2-1/4+(y+1/2)^2-1/4=12\Rightarrow\\\\\Rightarrow (x+1/2)^2+(y+1/2)^2=12+1/2\Rightarrow (x+1/2)^2+(y+1/2)^2=25/2

and we want the maximum and minimum of the paraboloid when (x,y) varies on the circumference we just found. That is, we want the maximum and minimum of  

\bf f(x,y)=x^2+y^2

subject to the constraint

\bf g(x,y)=(x+1/2)^2+(y+1/2)^2-25/2=0

Now we have

\bf \nabla f=(\displaystyle\frac{\partial f}{\partial x},\displaystyle\frac{\partial f}{\partial y})=(2x,2y)\\\\\nabla g=(\displaystyle\frac{\partial g}{\partial x},\displaystyle\frac{\partial g}{\partial y})=(2x+1,2y+1)

Let \bf \lambda be the Lagrange multiplier.

The maximum and minimum must occur at points where

\bf \nabla f=\lambda\nabla g

that is,

\bf (2x,2y)=\lambda(2x+1,2y+1)\Rightarrow 2x=\lambda (2x+1)\;,2y=\lambda (2y+1)

we can assume (x,y)≠ (-1/2, -1/2) since that point is not in the restriction, so

\bf \lambda=\displaystyle\frac{2x}{(2x+1)} \;,\lambda=\displaystyle\frac{2y}{(2y+1)}\Rightarrow \displaystyle\frac{2x}{(2x+1)}=\displaystyle\frac{2y}{(2y+1)}\Rightarrow\\\\\Rightarrow 2x(2y+1)=2y(2x+1)\Rightarrow 4xy+2x=4xy+2y\Rightarrow\\\\\Rightarrow x=y

Replacing in the constraint

\bf (x+1/2)^2+(x+1/2)^2-25/2=0\Rightarrow (x+1/2)^2=25/4\Rightarrow\\\\\Rightarrow |x+1/2|=5/2

from this we get

<em>x=-1/2 + 5/2 = 2 or x = -1/2 - 5/2 = -3 </em>

<em> </em>

and the candidates for maximum and minimum are (2,2) and (-3,-3).

Replacing these values in f, we see that

f(-3,-3) = 9+9 = 18 is the maximum and

f(2,2) = 4+4 = 8 is the minimum

b)

Since the square of the distance from any given point (x,y) on the paraboloid to (0,0) is f(x,y) itself, the maximum and minimum of the distance are reached at the points we just found.

We have then,

(-3,-3) is the farthest from the origin

(2,2) is the closest to the origin.

3 0
3 years ago
The weight of a full steel bead tire is approximately 800 grams, while a lighter wheel weighs only 700 grams. What is the weight
SIZIF [17.4K]

800= about 1.76 lbs

700= about 1.54 lbs


(there are about 453.5 grams in a pound

4 0
4 years ago
Read 2 more answers
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