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kondaur [170]
3 years ago
10

Consider the system of equations.

Mathematics
1 answer:
Xelga [282]3 years ago
3 0

Answer:

D and C

Step-by-step explanation:

Given the 2 equations

3x - y = 5 → (1)

2x + 3y = - 15 → (2)

Multiplying (1) by 3 and adding to (2) will eliminate the y- term

9x - 3y = 15 → (3)

Add (2) and (3) term by term to eliminate y

11x + 0 = 0

11x = 0 ⇒ x = 0

Substitute x = 0 into either of the 2 equations and solve for y

Substituting into (2)

2(0) + 3y = - 15

0 + 3y = - 15

3y = - 15 ( divide both sides by 3 )

y = - 5

solution is (0, - 5 )

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Based on the graph, what are the approximate solutions to the equation −3x + 8 = (0.25)x?
storchak [24]

Let

f(x)=3x+8

g(x)=0.25^{x}

in this problem

f(x)=g(x)

so

3x+8=0.25^{x}

using a graph tool

the solution is the intersection of both graphs

see the attached figure

the solutions are

x=-1.89

x=2.66

6 0
4 years ago
Canadians who visit the United States often buy liquor and cigarettes, which are much cheaper in the United States. However, the
victus00 [196]

Answer:

Probability of bringing a bottle of liquor into the country that is, the probability of bringing 1 bottle liquor into the country = P(B) = 0.31

The probability of not bringing a bottle of liquor into the country, that is, the probability of bringing 0 bottle liquor into the country = P(B') = 0.69

Probability distribution of bottle liquor

Let X represent the random variable of the number of bottle liquor brought into the country by a person

X | P(X)

0 | 0.69

1 | 0.31

Step-by-step explanation:

The joint probability distribution for the number of bottles of liquor and the number of cartons of cigarettes imported by Canadians who have visited the United States for 2 or more days is given in the question as

V | B

C | 0 | 1

0 | 0.62 | 0.16

1 | 0.07 | 0.15

Note that B = bottle liquor

C = Carton cigarettes

V is each variable

Let the probability of bringing a bottle of liquor into the country be P(B), that is, the probability of bringing 1 bottle liquor into the country.

The probability of not bringing a bottle of liquor into the country is P(B'), that is, the probability of bringing 0 bottle liquor into the country.

Let the probability of bringing a carton of cigarettes into the country be P(C), that is, the probability of bringing 1 carton cigarettes into the country.

The probability of not bringing a carton of cigarettes into the country is P(C'), that is, the probability of bringing 0 carton cigarettes into the country.

From the joint probability table, we can tell that

P(B n C) = 0.15

P(B n C') = 0.16

P(B' n C) = 0.07

P(B' n C') = 0.62

Find the marginal probability distribution of the number of bottles imported.

Probability of bringing a bottle of liquor into the country that is, the probability of bringing 1 bottle liquor into the country = P(B)

P(B) = P(B n C) + P(B n C') = 0.15 + 0.16 = 0.31

The probability of not bringing a bottle of liquor into the country, that is, the probability of bringing 0 bottle liquor into the country = P(B')

P(B') = P(B' n C) + P(B' n C') = 0.07 + 0.62 = 0.69

Probability distribution of bottle liquor

Let X represent the random variable of the number of bottle liquor brought into the country by a person

X | P(X)

0 | 0.69

1 | 0.31

Hope this Helps!!!

8 0
3 years ago
Sydney worked 1,750 hours last year this year she worked 1,975 hours how many hours has she worked in the last past two years
Maslowich
1750+1975=3725 so she worked 3725 hours
6 0
4 years ago
Evaluate 156 divided by(8x+14)when x=8 i am only in 6th grade be nice
VikaD [51]
So first we have to find out what the bottom number is so

8x+14
subsitute 8 for x
8(8)+14
64+14
78

so 156/78
an easy way to do this is to factor it out and find the 'ones' like 4/8=1/2 times 4/4 (4/4=1 and can be canceled out)
*=times
156=2*2*3*13
78=2*3*13

so (2*2*3*13)/(2*3*13)
2/1 times (2*3*13)/(2*3*13)
we can cross out the (2*3*13) and get
2 as the answer
6 0
3 years ago
Read 2 more answers
for the problem 135 divided by 5 draw two different ways to break apart the array use the distributive property to write product
Zanzabum
So first use long divsion and dived 135 by 5 and make that many groups containg 5 or the other way around as you are distributing the prouduct
8 0
3 years ago
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