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2 years ago

at a highschool, the length of a class period is 40 minutes. What is the length, in hours, of a class period at the high school?

Mathematics

1 answer:

Viktor [21]2 years ago

4 0

Answer:

2/3 hours

Step-by-step explanation:

40 minutes = 40/60 = 2/3 hours

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Make sure you show all your work for full points. What is y? yz 42 26 55

svetoff [14.1K]

Y equal 55 .........

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2 years ago

Bought three boxes totaling 151 book cost 50% more than the other two what was the price of the more expensive book 80 85 90 95

GenaCL600 [577]

Two cheaper books = x
more expensive = 1.5x
so, 2.5x=150
150/2.5=x=60
therefore the more expensive book = 90

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3 years ago

Help me please! Am horrible at math.

lesya692 [45]

Answer:

Step-by-step explanation:

For a. the 14.7 represents the pressure that the air puts on you all the time.

For b. the d represents the depth you go under the surface of the water.

For c. we have to solve p(d) when d = 8:

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2 years ago

The location of point V is (-3,3). The location of point X is (9,13). Determine the location of point W which is 3/4 of the way

Inga [223]

ANSWER

$W(\frac{9}{7},\frac{51}{7} )$

EXPLANATION

We want to find the coordinates of the point W(x,y) which divides V(-3,3) and X(9,13) in the ratio m:n=3:4.

The x-coordinate of this point is given by:

$x= \frac{mx_2+nx_1}{m + n}$

$x= \frac{3(9)+4( - 3)}{4 + 3}$

$x= \frac{21 - 12}{4 + 3}$

$x= \frac{9}{7}$

The y-coordinates is given by;

$y= \frac{my_2+ny_1}{m + n}$

$y= \frac{3(13)+4( 3)}{4 + 3}$

$y= \frac{39+12}{4 + 3}$

$y= \frac{51}{7}$

Hence

$W(\frac{9}{7},\frac{51}{7} )$

3 0

3 years ago

Simplify (9k6 + 8k4 - 6k2)(4k2 - 5)

Tasya [4]

Answer:

$36k^8-13k^6-64k^4+30k^2$

Step-by-step explanation:

$36k^8-13k^6-64k^4+30k^2\\9k^6*(4k^2-5)+8k^4*(4k^2-5)-6k^2*(4x^2-5)\\36k^8-45k^6+8k^4*(4k^2-5)-6k^2*(4x^2-5)\\36k^8-45k^6+32k^6-40k^4-6k^2*(4x^2-5)\\36k^8-45k^6+32k^6-40k^4-24k^4+30k^2\\36k^8-13k^6-40k^4-24k^4+30k^2\\36k^8-13k^6-64k^4+30k^2$

8 0

3 years ago