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2 years ago

14

Enzo’s mean score is 44. Zahra’s mean score is 38. The difference between the mean scores is about how many times the mean absol

ute deviation of the data sets, to the nearest whole number?

1 answer:

konstantin123 [22]2 years ago

4 0

The correct answer is 1.

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A quality control inspector has drawn a sample of 19 light bulbs from a recent production lot. If the number of defective bulbs

Inessa05 [86]

Answer:

0.0016283

Step-by-step explanation:

Given that:

Proportion of defective bulbs, p = 30% = 0.3

Sample size, n = 19 bulbs

Probability that the lot will pass inspection :

P(none of the 19 is defective) Or P(only one of the 19 is defective)

P(none of the 19 is defective) = (1 - p) ^n = (1 - 0.3)^19 ; 0.7^19

0.7^19 = 0.0011398

P(only one of the 19 is defective) :

P(1 defective) * P(18 not defective )

(0.3) * (1 - 0.3)^18

0.3 * 0.7^18

0.3 * 0.001628413597910449 = 0.0004885

Hence,

P(none of the 19 is defective) + P(only one of the 19 is defective)

0.0011398 + 0.0004885) = 0.0016283

8 0

3 years ago

1. Rich wants to buy a coat priced at x dollars. It is on sale for 20% off. He must

alexandr1967 [171]

Answer: $x-0.20x+0.0725x$

Step-by-step explanation:

Let x be the price. 20% (0.20) 7.25% (0.0725)

$x-0.20x+0.0725x$

6 0

2 years ago

What is the inverse of x^2-4x+5

lisabon 2012 [21]

we are given

$f(x)=x^2-4x+5$

Since, we have to find inverse of this function

step-1: we set f(x)=y

$y=x^2-4x+5$

step-2: switch x and y

$x=y^2-4y+5$

step-3: Solve for y

$y^2-4y+(5-x)=0$

now, we can use quadratic formula

$y=\frac{4+\sqrt{4^2-4(5-x)} }{2}$

$f^{-1}(x)=\sqrt{x-1}+2$

or

$f^{-1}(x)=-\sqrt{x-1}+2$ ..............Answer

6 0

2 years ago

Help me plsss in need help there is a picture

Kryger [21]

Answer:

Division Expression - 7 ÷ 3

Unit Form - 21 thirds ÷ 3 = 7

Improper Fraction 7/3

Step-by-step explanation:

Hope this helps!! <3

7 0

2 years ago

Two brothers want to share a large field equally.

Elan Coil [88]

Yes, the partition gives the two brothers equal shares.

Step-by-step explanation:

Step 1:

Assume the entire field has an area of B. So one brother takes $\frac{1}{12} B$ , $\frac{1}{6}B$ , and $\frac{1}{4} B$

So we need to calculate how much this brother takes in terms of B.

To do this we calculate how much $\frac{1}{12} B + \frac{1}{6} B + \frac{1}{4} B$ is.

Step 2:

To add $\frac{1}{12} B + \frac{1}{6} B + \frac{1}{4} B$ ,

First take the LCM of the denominators 12, 6, and 4

The LCM is 12, we multiply the denominator to get the LCM value, this same value is multiplied to the numerator too.

$\frac{1}{12} B + \frac{1}{6} B + \frac{1}{4} B = \frac{1(1)}{12(1)} B + \frac{1(2)}{6(2)} B + \frac{1(3)}{4(3)} B \\\\\frac{1}{12} B + \frac{1}{6} B + \frac{1}{4} B= \frac{1B +2B+3B}{12} = \frac{B}{2}$

Step 3:

One brother gets $\frac{1}{2} B$ , so we need to calculate how much the other brother gets.

The other brother's share = $B - \frac{1}{2} B = \frac{1}{2}B$

So both the brothers get equal shares

7 0

3 years ago