Answer 28.
Possible values for the three factors of -3
- 1, -1 and 3
- -1.5, 1 and 2
- 1.5, -1 and 2
- 1.5, 1 and -2
Answer 29.
The product of two nonzero integers will be less than or equal to both of the integers if they are multiplied by number itself and one or by number itself and one with negative sign.
Answer 30.
The sign of the product of three integers with the same sign will be positive or negative. If odd number of same sign is multiplied, the product will be of that sign.
(+) (+) (+) = (+)
(-) (-) (-) = (-)
Answer:
Third step is incorrect. The correct factored form is (x-1)(2x-5).
Step-by-step explanation:
The given expression is
We need to find the factored form of this expression.
Step 1: Given
Step 2: Splitting the middle term method, the middle term can be written as (-5x-2x).
Step 3: Taking out common factors from each parenthesis.
Step 4: Taking out common factors.
Therefore, the third step is incorrect. The correct factored form is (x-1)(2x-5).
Answer:
x=2
Step-by-step explanation:
5x +(3-1) =12
5x +2 =12
5x =12-2
5x =10
x =10÷5
x =2
1. Start with ΔCIJ.
- ∠HIC and ∠CIJ are supplementary, then m∠CIJ=180°-7x;
- the sum of the measures of all interior angles in ΔCIJ is 180°, then m∠CJI=180°-m∠JCI-m∠CIJ=180°-25°-(180°-7x)=7x-25°;
- ∠CJI and ∠KJA are congruent as vertical angles, then m∠KJA =m∠CJI=7x-25°.
2. Lines HM and DG are parallel, then ∠KJA and ∠JAB are consecutive interior angles, then m∠KJA+m∠JAB=180°. So
m∠JAB=180°-m∠KJA=180°-(7x-25°)=205°-7x.
3. Consider ΔCKL.
- ∠LFG and ∠CLM are corresponding angles, then m∠LFG=m∠CLM=8x;
- ∠CLM and ∠CLK are supplementary, then m∠CLM+m∠CLK=180°, m∠CLK=180°-8x;
- the sum of the measures of all interior angles in ΔCLK is 180°, then m∠CKL=180°-m∠CLK-m∠LCK=180°-(180°-8x)-42°=8x-42°;
- ∠CKL and ∠JKB are congruent as vertical angles, then m∠JKB =m∠CKL=8x-42°.
4. Lines HM and DG are parallel, then ∠JKB and ∠KBA are consecutive interior angles, then m∠JKB+m∠KBA=180°. So
m∠KBA=180°-m∠JKB=180°-(8x-42°)=222°-8x.
5. ΔABC is isosceles, then angles adjacent to the base are congruent:
m∠KBA=m∠JAB → 222°-8x=205°-7x,
7x-8x=205°-222°,
-x=-17°,
x=17°.
Then m∠CAB=m∠CBA=205°-7x=86°.
Answer: 86°.
