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Fynjy0 [20]
3 years ago
6

Ms. Canton went to the store to buy grapes. She bought four bunches of purple grapes. Each bunch had the same amount of grapes (

x) She also bought two bunches of green grapes.Each bunch of green grapes had the same amount of grapes in them (y). Write an expression that will show how many bunches of grapes Ms. Canton purchased. *
Mathematics
2 answers:
VikaD [51]3 years ago
7 0
4x+2y because there’s four bags of grapes and two bunches of each and you don’t know the amount of grapes in each of them.
Licemer1 [7]3 years ago
6 0
Answer:
4x+2y

Explanation:
x represents the purple grapes in one bunch, while y represents the green grapes in one bunch.
Given: 4 bunches of purple grapes (x), 2 bunches of green grapes (y)
Combine to get the expression 4x +2y
Hope this helps
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Answer:

The counterclockwise circulation is \frac{7}{12} and the outward flux is \frac{11}{15}

Step-by-step explanation:

We are given the field F(x,y) = (7xy,2y^2). A picture of the region and the path we are considering is attached. Recalll the following theorems.

Given a field of the form F(x,y)=(f(x,y),g(x,y) with f,g having continous partial derivates, C is a closed path counterclockwise oriented, R is the region enclosed by C and n is the normal vector pointing outwards of the path C. Then

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\oint_C F\cdot n ds =\iint_R (\frac{\partial f}{dx}+ \frac{\partial g}{dy} dA (This one calculates the outward flux)

Then, recall that in our case f(x,y) = 7xy, g(x,y)=2y^2[/tex]. Then

\frac{\partial f}{dx} = 7y,\frac{\partial f}{dy} = 7x

\frac{\partial g}{dx}=0, \frac{\partial g}{dy} = 4y.

Note that we just need to describe our region R. The region R lies between the parabola y=x^2 and the line y=x. Thus, one way to describe the region is as follows 0\leq x \leq 1, x^2\leq y \leq x. Then, using the previous results, we get that

\oint_C F\cdot dr =\int_{0}^{1}\int_{x^2}^{x}7x-0dydx = 7\int_{0}^1x(x-x^2)dx = 7 \left.(\frac{x^3}{3}-\frac{x^4}{4})\right|_{0}^1 = 7(\frac{1}{3}-\frac{1}{4}) = \frac{7}{12} (circulation)

\oint_C F\cdot n ds=\int_{0}^{1}\int_{x^2}^{x}7y+4ydydx = \frac{11}{2}\int_{0}^1\left.y^2\right_{x^2}^{x}dx = \frac{11}{2}\int_{0}^{1}x^2-x^4 dx = \frac{11}{2}\left(\frac{x^3}{3}-\frac{x^5}{5})\right|_{0}^{1}=\frac{11}{2}(\frac{1}{3}-\frac{1}{5})=\frac{11}{15}(flux)

5 0
3 years ago
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Step-by-step explanation:

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