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Nuetrik [128]
3 years ago
6

In Florida no fault insurance is optional for owners of a vehicle

Computers and Technology
1 answer:
Elena-2011 [213]3 years ago
7 0
It is false, Its obligatory. 
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1. How many bits would you need to address a 2M × 32 memory if:
Dominik [7]

Answer:

  1. a) 23       b) 21
  2. a) 43        b) 42
  3. a) 0          b) 0

Explanation:

<u>1) How many bits is needed to address a 2M * 32 memory </u>

2M = 2^1*2^20, while item =32 bit long word

hence ; L = 2^21 ; w = 32

a) when the memory is byte addressable

w = 8;  L = ( 2M * 32 ) / 8 =  2M * 4

hence number of bits =  log2(2M * 4)= log2 ( 2 * 2^20 * 2^2 ) = 23 bits

b) when the memory is word addressable

W = 32 ; L = ( 2M * 32 )/ 32 = 2M

hence the number of bits = log2 ( 2M ) = Log2 (2 * 2^20 ) = 21 bits

<u>2) How many bits are required to address a 4M × 16 main memory</u>

4M = 4^1*4^20 while item = 16 bit long word

hence L ( length ) = 4^21 ; w = 16

a) when the memory is byte addressable

w = 8 ; L = ( 4M * 16 ) / 8 = 4M * 2

hence number of bits = log 2 ( 4M * 2 ) = log 2 ( 4^1*4^20*2^1 ) ≈ 43 bits

b) when the memory is word addressable

w = 16 ; L = ( 4M * 16 ) / 16 = 4M

hence number of bits = log 2 ( 4M ) = log2 ( 4^1*4^20 ) ≈ 42 bits

<u>3) How many bits are required to address a 1M * 8 main memory </u>

1M = 1^1 * 1^20 ,  item = 8

L = 1^21 ; w = 8

a) when the memory is byte addressable

w = 8 ; L = ( 1 M * 8 ) / 8 = 1M

hence number of bits = log 2 ( 1M ) = log2 ( 1^1 * 1^20 ) = 0 bit

b) when memory is word addressable

w = 8 ; L = ( 1 M * 8 ) / 8 = 1M

number of bits = 0

5 0
2 years ago
A security utility program that scans the system for small programs that interfere with how a computer functions are _____ utili
Aneli [31]

Answer:

A security utility program that scans the system for small programs that interfere with how a computer functions are _____ utilities.

Explanation:

7 0
3 years ago
Create a new Die object. (Refer to Die.html for documentation.)Create a loop that will iterate at least 100 times. In the loop b
hjlf

Answer:

Java code is given below

Explanation:

import java.util.Random;

class Die{

private int sides;

public Die(){

sides = 6;

}

public Die(int s){

sides = s;

}

public int Roll(){

Random r = new Random();

return r.nextInt(6)+1;

}

}

class DieRoll{

public static void main(String[] args) {

Die die = new Die();

int arr[] = new int[6];

for(int i=0; i<6; i++)

arr[i] = 0;

for(int i=0; i<100; i++){

int r = die.Roll();

arr[r-1]++;

}

for(int i=0; i<6; i++)

System.out.println((i+1)+" was rolled "+arr[i]+" times.");

}

}

8 0
3 years ago
As data travels further over a wavelength or frequency, what goes down?
LUCKY_DIMON [66]

As data travels further over a wavelength or frequency, the radiation type goes down.

<h3>What is an electromagnetic spectrum?</h3>

An electromagnetic spectrum can be defined as a range of frequencies and wavelengths into which an electromagnetic wave is distributed into.

In Science, the electromagnetic spectrum consist of the following types of energy from highest to lowest frequency and shortest to longest wavelength:

  • Gamma rays
  • X-rays
  • Ultraviolet radiation
  • Visible light
  • Infrared radiation
  • Microwaves
  • Radio waves

In this context, we can infer and logically deduce that as data travels further over a wavelength or frequency within the electromagnetic spectrum, the radiation type goes down.

Read more on electromagnetic spectrum here: brainly.com/question/23423065

#SPJ1

5 0
1 year ago
Differentiate between system software and application software
vodomira [7]

Answer:

system software is the software which control overall operation of the computer . For eg. Ms.dos ,window 2003 ,etc whereas application software is a software which work on the top of operating system to solve number of problems .For eg. Ms.word,Ms.excel,etc

3 0
2 years ago
Read 2 more answers
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