Answer:
One-to-one is the answer because there is one project and one employee working on one project.
Answer:
The Rouché-Capelli Theorem. This theorem establishes a connection between how a linear system behaves and the ranks of its coefficient matrix (A) and its counterpart the augmented matrix.
![rank(A)=rank\left ( \left [ A|B \right ] \right )\:and\:n=rank(A)](https://tex.z-dn.net/?f=rank%28A%29%3Drank%5Cleft%20%28%20%5Cleft%20%5B%20A%7CB%20%5Cright%20%5D%20%5Cright%20%29%5C%3Aand%5C%3An%3Drank%28A%29)
Then satisfying this theorem the system is consistent and has one single solution.
Explanation:
1) To answer that, you should have to know The Rouché-Capelli Theorem. This theorem establishes a connection between how a linear system behaves and the ranks of its coefficient matrix (A) and its counterpart the augmented matrix.
![rank(A)=rank\left ( \left [ A|B \right ] \right )\:and\:n=rank(A)](https://tex.z-dn.net/?f=rank%28A%29%3Drank%5Cleft%20%28%20%5Cleft%20%5B%20A%7CB%20%5Cright%20%5D%20%5Cright%20%29%5C%3Aand%5C%3An%3Drank%28A%29)

Then the system is consistent and has a unique solution.
<em>E.g.</em>

2) Writing it as Linear system


3) The Rank (A) is 3 found through Gauss elimination


4) The rank of (A|B) is also equal to 3, found through Gauss elimination:
So this linear system is consistent and has a unique solution.
Answer:
game 1: roblox, its not technically a game, however it contains game that could fall under more than one category. Game 2: Dungeons and Dragons could fall under role play and also adventure
Explanation:
Static void DashedLine(int n){ if (n>1) Console.WriteLine(new String('-', n));}
Answer:


Explanation:
Binary and hexadecimal values have the following pair equivalences.
















We convert from binary to hexadecimal selecting groups of 4 binary from the binary code, from the least significant bits(at the right) to the most significant bits(at the left). The conversion is an hexadecimal "string" from the last group you converted to the first. So:
(a) %100011100101



So

(b) %1011001111



