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myrzilka [38]
3 years ago
7

Which statement is true about encoding in Python?

Computers and Technology
1 answer:
vovangra [49]3 years ago
6 0

Answer:

In Python 3, strings are automatically encoded using Unicode.

Explanation:

i just tookthe test

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All resources are limited. Which of the following is NOT a resource?
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Give your definition of a view. Based on the Academic Database, identify and describe a scenario where it would be necessary to
il63 [147K]

Answer:

A database view is a searchable object in a database that is defined by a query. Though a view doesn't store data, some refer to a views as “virtual tables,” you can query a view like you can a table. A view can combine data from two or more table, using joins, and also just contain a subset of information.

Explanation:

A database view is a subset of a database that is based on a query that runs on one or more database tables. Database views are saved in the database as named queries and can be used to save complete queries that are frequently used.

7 0
3 years ago
TV show information can either keep track of the number of viewers per show or the name of a show. Information is kept in a file
Elza [17]

Answer:

See explaination for Program source code.

Explanation:

The program source code below.

#include <iostream>

#include <fstream>

#include <vector>

using namespace std;

class Show

{

private:

string title;

int viewers;

public:

Show()

{

this->title = "";

this->viewers = 0;

}

Show(string title, int viewers)

{

this->title = title;

this->viewers = viewers;

}

string getTitle(){ return this->title; }

int getViewers(){ return this->viewers; }

};

int main()

{

vector<Show> shows;

vector<string> titles;

vector<int> viewers;

ifstream inFile1("file1.txt");

ifstream inFile2("file2.txt");

string line1, line2;

if(!inFile1.is_open() || !inFile2.is_open())

{

cout << "Either of the files could not be found!\n";

exit(0);

}

getline(inFile1, line1);

if(line1.compare("Show") == 0)

{

while(getline(inFile1, line1))

{

titles.push_back(line1);

}

inFile1.close();

}

getline(inFile2, line2);

if(line2.compare("Viewer") == 0)

{

while(getline(inFile2, line2))

{

viewers.push_back(stod(line2));

}

inFile2.close();

}

for(int i = 0; i < titles.size(); i++)

{

shows.push_back(Show(titles[i], viewers[i]));

}

// display all the show details

cout << "\nALL SHOWS:\n----------\n";

for(Show show : shows)

{

cout << "Title: " << show.getTitle() << ", Number of viewers: " << show.getViewers() << endl;

}

cout << endl;

return 0;

}

See attachment for output

3 0
3 years ago
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