Answer:
17. 42
18. 12
19. 12
20. 12
Step-by-step explanation:
Simply substitute the given values into the variables. So if m = 6 and n = 2:
7m = 7(6) = 42
6n = 6(2) = 12
mn = (6)(2) = 12
3m - 6 = 3(6) - 6 = 18 - 6 = 12
Answer:
The answer is A. If two polygons are congruent, then they are similar
Step-by-step explanation:
Just took the test!
Answer:
The horizontal distance between the parking lot and the launch site is 470 meters
Step-by-step explanation:
Let
x-----> the horizontal distance between the parking lot and the launch site
we know that
The tangent of angle of 12 degrees is equal to divide the altitude of 100 meters by the horizontal distance
so
tan(12°)=100/x
Solve for x
x=100/tan(12°)=470 meters
Answer:
We can think that the line of the kite is the hypotenuse of a triangle rectangle, and the altitude is one of the cathetus of the triangle.
And we know that it makes an angle of 65° with the horizontal (i guess this is measured between the hypotenuse and the horizontal adjacent to the kite.
This angle is complementary to the top angle of our triangle rectangle, such that A + 65° = 90°
A = 90° - 65° = 25°
Then the altitude of the kite is the adjacent cathetus to this angle.
We can use the relation:
sin(A) = Adjacent cathetus/hypotenuse.
Sin(25°) = X/350ft
Sin(25°)*350ft = X = 147.9m
