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3 years ago

5

the circus sets up chairs in rows with 9 seats in each row will need to be set up if 513 people are expected to attend the show

?

2 answers:

UNO [17]3 years ago

6 0

57 rows, because 513/9=57

antoniya [11.8K]3 years ago

4 0

57 rows because 513 divided by 9 = 57

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What is the difference between the smallest six digit number and the greatest four digit number

drek231 [11]

The smallest (whole number ) 6 digit number is 1,000,000
The greatest (whole number 4 digit number is 9,999
The difference between them means to subtract the four digit number from the 6 digit number.
The difference is 990,001

I would not consider 000001 to be a 6 digit number (in case this is supposed to be a trick question.)

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4 years ago

Read 2 more answers

use Taylor's Theorem with integral remainder and the mean-value theorem for integrals to deduce Taylor's Theorem with lagrange r

Vadim26 [7]

Answer:

As consequence of the Taylor theorem with integral remainder we have that

$f(x) = f(a) + f'(a)(x-a) + \frac{f''(a)}{2!}(x-a)^2 + \cdots + \frac{f^{(n)}(a)}{n!}(x-a)^n + \int^a_x f^{(n+1)}(t)\frac{(x-t)^n}{n!}dt$

If we ask that $f$ has continuous $(n+1)$ th derivative we can apply the mean value theorem for integrals. Then, there exists $c$ between $a$ and $x$ such that

$\int^a_x f^{(n+1)}(t)\frac{(x-t)^k}{n!}dt = \frac{f^{(n+1)}(c)}{n!} \int^a_x (x-t)^n d t = \frac{f^{(n+1)}(c)}{n!} \frac{(x-t)^{n+1}}{n+1}\Big|_a^x$

Hence,

$\int^a_x f^{(n+1)}(t)\frac{(x-t)^k}{n!}d t = \frac{f^{(n+1)}(c)}{n!} \frac{(x-t)^{(n+1)}}{n+1} = \frac{f^{(n+1)}(c)}{(n+1)!}(x-a)^{n+1} .$

Thus,

$\int^a_x f^{(n+1)}(t)\frac{(x-t)^k}{n!}d t = \frac{f^{(n+1)}(c)}{(n+1)!}(x-a)^{n+1}$

and the Taylor theorem with Lagrange remainder is

$f(x) = f(a) + f'(a)(x-a) + \frac{f''(a)}{2!}(x-a)^2 + \cdots + \frac{f^{(n)}(a)}{n!}(x-a)^n + \frac{f^{(n+1)}(c)}{(n+1)!}(x-a)^{n+1}$ .

Step-by-step explanation:

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3 years ago

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Rasek [7]

Combine like terms

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( -6x^2+2x^2)+(2y-5y)+(-1+3)

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Answer : C

I hope that's help !

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3 years ago

Can someone help please?

ratelena [41]

Answer: It is TRUE. A point in a linear equation can be the solution to said equation.

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3 years ago

Outline the process for Inscribing an equilateral triangle in a circle. Perform the construction in GeoGebra, and take a

mezya [45]

Answer:

I don't use Geogebra, but the following procedure should work.

Step-by-step explanation:

Construct a circle A with point B on the circumference.

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3 years ago