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Kazeer [188]
3 years ago
10

G(x) = 9x plug in g(9)​

Mathematics
2 answers:
Schach [20]3 years ago
8 0

Answer:

g(9) = 81

Step-by-step explanation:

g(x) = 9x

g(9) = 9(9) = 81

monitta3 years ago
7 0

Answer:

81

Step-by-step explanation:

replace x with 9 so it's 9x9 which is 81

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Round up 64,781 to the nearest ten thousand
velikii [3]

64,781

/\

|

60,000

---

hope it helps

7 0
3 years ago
Read 2 more answers
What percent is 700 paise of 7 rupees​
dlinn [17]

To find :-

  • What percent is 700 paise of 7 rupees .

Solution :-

As we know that,

→ ₹1 = 100 p

So ,

→ 700p = ₹ 700/100

→ 700p = ₹ 7

Now let's calculate % , as ;

→ 700p / ₹7 * 100 %

→ ₹7/₹7 *100 %

→ 1 *100%

→ 100%

<u>Hence</u><u> </u><u>7</u><u>0</u><u>0</u><u>p</u><u> </u><u>is </u><u>100%</u><u> </u><u>of </u><u>₹</u><u>7</u><u> </u><u>.</u>

I hope this helps.

6 0
3 years ago
PLEASE HELP.<br> What is the value of X in the photo below? (please show work)
Tom [10]

Value of x is 5. I remember doing this last year..

35a+45b=80

then we would do 99-80, and that gives us the value of c, 19

5 0
3 years ago
145+ (-15) + (-188) =<br> O 56<br> 0 -58<br> O 358<br> O 58
mario62 [17]

Q) 145+ (-15) + (-188) = ?

→ 145+ (-15) + (-188)

→ {145 - 15} - 188

→ 130 - 188

→ -58 is the solution.

3 0
3 years ago
find the orthogonal projection of v= [19,12,14,-17] onto the subspace W spanned by [ [ -4,-1,-1,3] ,[ 1,-4,4,3] ] proj w (v) = [
12345 [234]
<h2>Answer:</h2>

Hence, we have:

proj_W(v)=[\dfrac{464}{21},\dfrac{167}{21},\dfrac{71}{21},\dfrac{-131}{7}]

<h2>Step-by-step explanation:</h2>

By the orthogonal decomposition theorem we have:

The orthogonal projection of a vector v onto the subspace W=span{w,w'} is given by:

proj_W(v)=(\dfrac{v\cdot w}{w\cdot w})w+(\dfrac{v\cdot w'}{w'\cdot w'})w'

Here we have:

v=[19,12,14,-17]\\\\w=[-4,-1,-1,3]\\\\w'=[1,-4,4,3]

Now,

v\cdot w=[19,12,14,-17]\cdot [-4,-1,-1,3]\\\\i.e.\\\\v\cdot w=19\times -4+12\times -1+14\times -1+-17\times 3\\\\i.e.\\\\v\cdot w=-76-12-14-51=-153

w\cdot w=[-4,-1,-1,3]\cdot [-4,-1,-1,3]\\\\i.e.\\\\w\cdot w=(-4)^2+(-1)^2+(-1)^2+3^2\\\\i.e.\\\\w\cdot w=16+1+1+9\\\\i.e.\\\\w\cdot w=27

and

v\cdot w'=[19,12,14,-17]\cdot [1,-4,4,3]\\\\i.e.\\\\v\cdot w'=19\times 1+12\times (-4)+14\times 4+(-17)\times 3\\\\i.e.\\\\v\cdot w'=19-48+56-51\\\\i.e.\\\\v\cdot w'=-24

w'\cdot w'=[1,-4,4,3]\cdot [1,-4,4,3]\\\\i.e.\\\\w'\cdot w'=(1)^2+(-4)^2+(4)^2+(3)^2\\\\i.e.\\\\w'\cdot w'=1+16+16+9\\\\i.e.\\\\w'\cdot w'=42

Hence, we have:

proj_W(v)=(\dfrac{-153}{27})[-4,-1,-1,3]+(\dfrac{-24}{42})[1,-4,4,3]\\\\i.e.\\\\proj_W(v)=\dfrac{-17}{3}[-4,-1,-1,3]+(\dfrac{-4}{7})[1,-4,4,3]\\\\i.e.\\\\proj_W(v)=[\dfrac{68}{3},\dfrac{17}{3},\dfrac{17}{3},-17]+[\dfrac{-4}{7},\dfrac{16}{7},\dfrac{-16}{7},\dfrac{-12}{7}]\\\\i.e.\\\\proj_W(v)=[\dfrac{464}{21},\dfrac{167}{21},\dfrac{71}{21},\dfrac{-131}{7}]

6 0
3 years ago
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