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tatiyna
2 years ago
15

Write an equation perpendicular to y=3/4x-1 that passes through the point (3,-3)

Mathematics
1 answer:
RSB [31]2 years ago
3 0
Y=.75x-1 im might be wrong i think im wrong but im not sure 
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PLEASE HELP WILL GIVE BRAINIEST AND A THANKS!!!!!<br><br><br> Write the equation of the line.
solong [7]
1.) y= 2/3x
2.)y= -1x + 1
3.)y= 2x + 1
4.)y= -2/3x + 1
The structure of the formula is y = mx + b.
m is the slope.
slope is found by rise over run.
b is the y intercept.
which is found by where the line is on the y axis
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2 years ago
Joe Bob wanted to find out how many hours of exercise the students at his school gets each week. He went to the school's gym and
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Although I am unsure what this question has to do with Mathematics, Joe Bob could simply say "How often do you work out in a week?"

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3 years ago
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Which expressions is not equivalent 2x^2+10x+12?
sergeinik [125]

Answer:

C

Step-by-step explanation:

First, factor the original expression:

As we can see, D is the same as above. Eliminate D.

Go through each of the answer choices.

A:

This is equivalent to what we factored. Eliminate A.

B:

This is again equivalent to what we factored. Eliminate B.

C:

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7 0
2 years ago
I need help with this problem
Arada [10]

Answer:

65.56°

Step-by-step explanation:

We know that if we take dot product of two vectors then it is equal to the product of magnitudes of the vectors and cosine of the angle between them

That is let p and q be any two vectors and A be the angle between them

So, p·q=|p|*|q|*cosA

⇒cosA=\frac{u.v}{|u||v|}

Given u=-8i-3j and v=-8i+8j

|u|=\sqrt{(-8)^{2}+ (-3)^{2}} =8.544

|v|=\sqrt{(-8)^{2}+ (8)^{2}} =11.3137

let A be angle before u and v

therefore, cosA=\frac{u.v}{|u||v|}=\frac{(-8)*(-8)+(-3)*(8)}{8.544*11.3137} =\frac{40}{96.664}

⇒A=arccos(\frac{40}{96.664} )=arccos(0.4138 )=65.56

Therefore angle between u and v is 65.56°

5 0
2 years ago
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