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2 years ago

HELP PLEASE!!!

Mathematics

1 answer:

olga nikolaevna [1]2 years ago

8 0

Answer: A, arithmetic

Step-by-step explanation:

An arithmetic sequence has a constant difference between each term. If she spend 36 dollars each week, the first week would be 36 the second week would be 72, and so on.

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HELP! This needs to be answered ASAP!

andriy [413]

Answer:

it will take 4 hours( I'm not so sure)

Step-by-step explanation:

$25x $15

------- = ------------- + 75

1h. 1h

25x = 100

x =100/25

x = 4

8 0

3 years ago

What is the area of this composite figure?

anygoal [31]

Answer:

Well, Your answer will be is D. 100 feet squared. Because,

1. Multiply 10x6 and 10x4.

2. Add 60 and 40, the results from the previous step.

3. You get 100, or 100 feet squared. Good Luck!

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2 years ago

Read 2 more answers

1. Kari is making copies at a local copy store of the program for her school play. She makes 52 copies and the total cost is $6.

Leona [35]

The first one is 2.78% second one is 3.8% third one is 4.5% and it will be 378

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3 years ago

Please help !! Correct and first answer I will give you brainesttttt!!!!! What is the equation of the line ?

Nonamiya [84]

Answer:

y = 3x + 5

Have a good day! :)

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3 years ago

Read 2 more answers

There are 2,000 eligible voters in a precinct. A total of 500 voters are randomly selected and asked whether they plan to vote f

Ann [662]

Answer:

$0.7 - 2.58 \sqrt{\frac{0.7(1-0.7)}{500}}=0.647$

$0.7 + 2.58 \sqrt{\frac{0.7(1-0.7)}{500}}=0.753$

And the 99% confidence interval would be given (0.647;0.753).

So the correct answer would be:

a. 0.647 and 0.753

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

Solution to the problem

The estimated population proportion for this case is:

$\hat p = \frac{350}{500}=0.7$

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 99% confidence interval the value of $\alpha=1-0.99=0.01$ and $\alpha/2=0.005$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=2.58$

And replacing into the confidence interval formula we got:

$0.7 - 2.58 \sqrt{\frac{0.7(1-0.7)}{500}}=0.647$

$0.7 + 2.58 \sqrt{\frac{0.7(1-0.7)}{500}}=0.753$

And the 99% confidence interval would be given (0.647;0.753).

So the correct answer would be:

a. 0.647 and 0.753

7 0

3 years ago