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Dmitry [639]
3 years ago
13

Please help.................

Mathematics
1 answer:
evablogger [386]3 years ago
7 0
It usually works well to do what the instructions tell you. Multiply each diameter by 3.14.

a) 3.14×6 cm = 18.84 cm

b) [can't read the picture]

d) 3.14×9 in = 28.26 in

e) 3.14×11 mm = 34.54 mm
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What is the number in scientific notation? 409,200,000,000
gavmur [86]
4.092 x 10 to the 11th power
7 0
3 years ago
Read 2 more answers
x = c1 cos(t) + c2 sin(t) is a two-parameter family of solutions of the second-order DE x'' + x = 0. Find a solution of the seco
igomit [66]

Answer:

x=-cos(t)+2sin(t)

Step-by-step explanation:

The problem is very simple, since they give us the solution from the start. However I will show you how they came to that solution:

A differential equation of the form:

a_n y^n +a_n_-_1y^{n-1}+...+a_1y'+a_oy=0

Will have a characteristic equation of the form:

a_n r^n +a_n_-_1r^{n-1}+...+a_1r+a_o=0

Where solutions r_1,r_2...,r_n are the roots from which the general solution can be found.

For real roots the solution is given by:

y(t)=c_1e^{r_1t} +c_2e^{r_2t}

For real repeated roots the solution is given by:

y(t)=c_1e^{rt} +c_2te^{rt}

For complex roots the solution is given by:

y(t)=c_1e^{\lambda t} cos(\mu t)+c_2e^{\lambda t} sin(\mu t)

Where:

r_1_,_2=\lambda \pm \mu i

Let's find the solution for x''+x=0 using the previous information:

The characteristic equation is:

r^{2} +1=0

So, the roots are given by:

r_1_,_2=0\pm \sqrt{-1} =\pm i

Therefore, the solution is:

x(t)=c_1cos(t)+c_2sin(t)

As you can see, is the same solution provided by the problem.

Moving on, let's find the derivative of x(t) in order to find the constants c_1 and c_2:

x'(t)=-c_1sin(t)+c_2cos(t)

Evaluating the initial conditions:

x(0)=-1\\\\-1=c_1cos(0)+c_2sin(0)\\\\-1=c_1

And

x'(0)=2\\\\2=-c_1sin(0)+c_2cos(0)\\\\2=c_2

Now we have found the value of the constants, the solution of the second-order IVP is:

x=-cos(t)+2sin(t)

3 0
3 years ago
Let f(x)=3x-6 and g(x)=x-2 find f(g(5))-ie. (f • g)(5) and its domain
Molodets [167]

Solution for f(g(5)):


The notation f(g(5)) or (f • g)(5) means that we first plug 5 into the function g(x), simplify, then plug the answer that we got to f(x). We will do this step-by-step:


Step 1: Plugging 5 to g(x)

g(5)=5-2=3


Step 2: Plugging the answer to f(x)

f(3)=3(3)-6=9-6=3


ANSWER: f(g(5)) is equal to 3.


Domain:


For the function f(g(x)), we can find the domain by analyzing the domains of each individual functions separately and excluding certain values depending on the restrictions from the outermost function.


However, since both functions have all real numbers as its domain, we will not need to do any exclusion anymore.


ANSWER: The domain of the function is all real numbers.

3 0
3 years ago
the length of a rectangle is 3 more than the width. if the area is 40 square inches, what are the dimensions.
tankabanditka [31]

40 3 .......................

5 0
3 years ago
Y=8x-3/-4x-10 has a vertical asymptote with equation(enter equation of the vertical asymptote
xz_007 [3.2K]

Answer:

x=-2.5 if the function is f(x)=\frac{8x-3}{-4x-10}

Step-by-step explanation:

y=\frac{8x-3}{-4x-10} has discontinuities when the denominator is 0.

You will either have a hole or a vertical asymptote depending on what happens to the numerator after you find when the bottom is 0.

That is whatever you found that makes the bottom 0, if it makes the top also 0 then you will have a hole at x=the number that made the bottom 0.

If it makes the top anything other than 0, then it is a vertical asymptote at x=the number you found that made the bottom 0.

Let's do this now.

When is -4x-10 equal to 0?

We have to solve the equation:

-4x-10=0

Add 10 on both sides:

-4x=10

Divide both sides by -4:

x=10/-4

Reduce by dividing top and bottom by 2:

x=5/-2

x=-5/2

or

x=-2.5  (if you want decimal form)

Now does it make the top 0? This is the deciding factor on whether you have a hole at x=-2.5 or a vertical asymptote at x=-2.5.

Let's see.

8(-2.5)-3=-23

Since the top is not 0 at x=-2.5 then you have a vertical asymptote at x=-2.5.

If the top were 0, then you would have had a hole at x=-2.5.

5 0
3 years ago
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