Complete question :
Mr. Nelson lost one of his students' test papers. He knows that the other 4 students scored as follows: 60, 62, 56, 57. He also knows that the average score is 59.2. What is the score on the missing paper?
Answer:
61
Step-by-step explanation:
Given the following :
Total number of students = 4 + 1 missing = 5
Score on the four avaliable papers = 60, 62, 56, 57
Average score of the 5 papers = 59.2
Score on missing paper :
Sum of each score / number of papers
Sum of each score = sum of available scores + missing score
Let missing score = m
(60 + 62 + 56 + 57 + m) = 235 + m
Recall:
Average = total sum / number of observations
Hence,
59.2 = (235 + m) / 5
59.2 × 5 = 235 + m
296 = 235 + m
m = 296 - 235
m = 61
Missing score = 61
Answer:
Step-by-step explanation:
A=LxW
Answer:
$1,080 please mark brainliest if satisfied
Step-by-step explanation:
1200 times 0.1 equals 120
1200 minus 120 equals 1080
Ok this is a bit complicated.
Total: 114 days
114 divided by 3 equals 38
38 times 2 equals 76
76 books, I think.
Assuming that is 2 right triangles sharing a side
height^2 = 20^2 -7^2
height^2 = 400 - 49
height^2 = 351
height =
<span>
<span>
<span>
18.7349939952
</span>
</span>
</span>
x^2 = 24^2 - <span>18.7349939952^2
x^2 = 576 -351
x^2 = 225
x = 15
</span>
