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3 years ago

14 + 5x = 3(-x + 3) -11 please show work step by step

Mathematics

1 answer:

mr Goodwill [35]3 years ago

3 0

14+5x=3(-x+3)-11

14+5x=-3x+9-11

14+5x=-3x-2

add 2 to both sides

16+5x=-3x

subtract 5x from both sides

16=-8x

divide both sides by -8

-2=x

Hope this helps! :)

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What is 4 1/4 * 4/34 =

Natali5045456 [20]

4 1/4 = 16/4

17/4 : 4/34 =

17/4 * 4/34 =

1/2

5 0

2 years ago

1. Samantha purchased a cookie(c) and carton of milk. If the milk cost $1.25 and the total amount of the items was $2.50. Which

Sergio039 [100]

Answer:

Step-by-step explanation:

First one is C+1.25=2.50

2. 5V=30

3. X-44

I hope this helped.

6 0

3 years ago

Read 2 more answers

BC - Round your answer to the nearest hundredth. B ? 35 A с 2.

mario62 [17]

Answer:

BC ≈ 1.40

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtract Property of Equality

Trigonometry

[Right Triangles Only] SOHCAHTOA
[Right Triangles Only] tanθ = opposite over adjacent

Step-by-step explanation:

Step 1: Identify

Angle θ = 35°

Opposite Leg BC = x

Adjacent Leg AC = 2

Step 2: Solve for x

Substitute [Tangent]: tan35° = x/2
Isolate x: 2tan35° = x
Rewrite: x = 2tan35°
Evaluate: x = 1.40042
Round: x ≈ 1.40

4 0

2 years ago

Read 2 more answers

The fan below has been stretched open as far as it will go to form a semi-circle.

Komok [63]

Answer:

Area of each sector= $12.6cm^2$

Step-by-step explanation:

We are given that

Length of each wooden od that connects the center of the fan to its edge ,r=12 cm

Total number of sectors=18

We have to find the approximate area of each sector.

Area of semi-circle= $\frac{1}{2}\pi r^2$

Using the formula

Area of fan= $\frac{1}{2}\pi (12)^2=72 \pi cm^2$

Area of each sector= $\frac{area\;of\;fan}{Total\;number\;of\;sectors}$

Area of each sector= $\frac{72\pi}{18}=\frac{72\times 3.14}{18} cm^2$

Where $\pi=3.14$

Area of each sector= $12.56cm^2\approx 12.6 cm^2$

5 0

3 years ago

Si se elige un estudiante de 15 años al azar, ¡Cual es la probabilidad de que no juegue futbol ni beisbol

Gekata [30.6K]

Respuesta:

20/31

Explicación paso a paso:

Para obtener respuestas a la Pregunta, contamos el punto ya que representa el número de estudiantes:

El número total de estudiantes se puede obtener contando todos los puntos en el diagrama de venn = 31

Número de estudiantes que juegan fútbol solos = número de puntos en la parte F del diagrama de Venn = 4

Número de estudiantes que juegan béisbol solos = número de puntos en la parte B del diagrama de Venn = 2

Número de estudiantes que juegan fútbol y béisbol = 5

La probabilidad de que un estudiante elegido al azar no juegue fútbol o béisbol:

El número de puntos que quedan fuera de los círculos se refiere al número de estudiantes que no participan en ninguno de los dos deportes = 20

P (sin béisbol o fútbol) = 20/31

7 0

3 years ago