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sergejj [24]
3 years ago
7

14 + 5x = 3(-x + 3) -11 please show work step by step

Mathematics
1 answer:
mr Goodwill [35]3 years ago
3 0

14+5x=3(-x+3)-11

14+5x=-3x+9-11

14+5x=-3x-2

add 2 to both sides

16+5x=-3x

subtract 5x from both sides

16=-8x

divide both sides by -8

-2=x

Hope this helps! :)

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Hi, can someone please help, and possibly explain the answer please.
mr_godi [17]

Answer:

x=\frac{-(-2)\±\sqrt{(-2)^2-4(3)(0)} }{2(3)}

Step-by-step explanation:

Quadratic formula: x=\frac{-b\±\sqrt{b^2-4ac} }{2a} when the equation is 0=ax^2+bx+c

The given equation is 1=-2x+3x^2+1. Let's first arrange this so its format looks like y=ax^2+bx+c:

1=-2x+3x^2+1

1=3x^2-2x+1

Subtract 1 from both sides of the equation

1-1=3x^2-2x+1-1\\0=3x^2-2x+0

Now, we can easily identify 3 as a, -2 as b and 0 as c. Plug these into the quadratic formula:

x=\frac{-b\±\sqrt{b^2-4ac} }{2a}\\x=\frac{-(-2)\±\sqrt{(-2)^2-4(3)(0)} }{2(3)}

I hope this helps!  

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Step-by-step explanation:

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