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3 years ago

Which two triangles are congruent by ASA? Explain.

Mathematics

1 answer:

yarga [219]3 years ago

7 0

Answer:

OGH and TCA

Step-by-step explanation:

that's quite easy...

the congruency criterion is ASA or Angle side Angle.

i.e. a side lying between two Angles.

so we have

GH = FN= CA

now, G=I= C

and H=N=A

it's pretty clear that G-GH-H = C-CA-A

(just to explain)

hence, the answer

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I need help I dont wear to start

Vinil7 [7]

Answer:

Yes! it is there are straight across from each other and will never touch Hope I helped!

3 0

3 years ago

If a/\2+1/a/\2=11, then a+1/a=?

Nadya [2.5K]

Answer:

$\pm \sqrt{13}$

Step-by-step explanation:

$\bigg(a + \frac{1}{a} \bigg)^{2} = {a}^{2} + \frac{1}{ {a}^{2} } + 2 \times a \times \frac{1}{a} \\ \\ \bigg(a + \frac{1}{a} \bigg)^{2} = 11 + 2 \\ \\ \bigg(a + \frac{1}{a} \bigg)^{2} = 13 \\ \\ \bigg(a + \frac{1}{a} \bigg) = \pm \sqrt{13}$

5 0

3 years ago

Question 9 (3 points)

Mila [183]

From the dot plot, we have that 90.91% of the students have 5 or more vowels in their first and last names.

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The dot plot states that:

2 students have 4 vowels in their first and last name.
3 students have 5 vowels.
8 students have 6 vowels.
9 students have 7 vowels.

Then:

Total of 2 + 3 + 8 + 9 = 22 students.
3 + 8 + 9 = 20 have or more vowels.

$p = \frac{20}{22} \times 100\% = 90.91\%$

90.91% of the students have 5 or more vowels in their first and last names.

A similar problem is given at brainly.com/question/14354536

5 0

3 years ago

I have no clue how to do this please help

mel-nik [20]

Answer:

Max = (6,0); min = (-2, 4)

Step-by-step explanation:

1. Summarize the constraints

$\text{Constraints} = \begin{cases}(a)\qquad 2x - y & \leq 12\\(b)\qquad 4x+ 2y & \geq 0\\(c) \qquad x + 2y & \leq 6\\ \end{cases}$

2. Optimization equation

z = 5x + 2y

3. Graph the constraints to identify the feasible region

See the figure below.

The "TRUE" regions for each graph are the shaded areas to the side of the line indicated by the arrows.

The "feasibility region" is the dark green area where all three areas overlap and all three conditions are satisfied.

5. Determine the points of intersection among the constraints

(i) Constraints (a) and (b)

$\begin{array}{rcr}2x - y & = & 12\\4x + 2y & = & 0\\4x - 2y & = & 24\\8x&=&24\\x & = & \mathbf{3}\\6 - y & = & 12\\-y & = &6\\y & = & \mathbf{-6}\\\end{array}\\$

The lines intersect at (3,-6).

(ii) Constraints (a) and (c)

$\begin{array}{rcr}2x - y & = & 12\\x + 2y & = & 6\\4x - 2y & = &24\\5x & = & 30\\x & = & \mathbf{6}\\6 + 2y & = & 6\\2y & = &0\\y & = & \mathbf{0}\\\end{array}$

The lines intersect at (6,0).

(iii) Constraints (b) and (c)

$\begin{array}{rcr}4x+ 2y &= & 0\\x + 2y &=& 6\\3x & = & -6\\x & = & \mathbf{-2}\\-2 +2y & = & 6\\2y & = &8\\y & = & \mathbf{4}\\\end{array}$

The lines intersect at (-2,4).

6. Determine the x- and y-intercepts of the feasible region

The five black dots at (3,-6), (6,0), and (-2,4) are the vertices of the polygon that represents the feasible region.

Each vertex is a possible maximum or minimum of z.

7. Calculate the maxima and minima

Calculate z at each of the vertices.

(i) At (-2,4)

z = 5x + 2y = 5(-2) + 2(4) = -10 + 8 = 2

(ii) At (3,-6)

z = 5(3) + 2(-6) = 15 - 12 = 3

(iii) At (6,0)

z = 5(6)+ 2(0) = 30 + 0 = 30

The maximum of z occurs at (6,0).

The minimum of z occurs at (-2, 4).

7 0

3 years ago

Lisa built a rectangular flower garden that is 4 feet wide and has a perimeter of 26 feet.

Bond [772]

Perimeter is l+l+w+w, or l*2+w*2. We know the width is 4 feet. 26=4*2+l*2
So first, find what 4*2 equals. The answer is 8. So subtract 8 from both sides. 4*2 Cancels out, and 26 changes to 18. Then, divide both sides by 2. The (*2) gets cancelled and 18 becomes 9. The length is 9 FEET.

:)-Kibeye

3 0

3 years ago

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