The data set below represents the ages of 11 kids in an after-school program. 10, 11, 8, 7, 6, 10, 7, 10, 9, 9, 12 Which box plo
Andreas93 [3]
Answer:
This is the answer because you need to find mean median mode range, first quertile, third quartile
Whisker plot below
Step-by-step explanation:
Mean (Average) 9
Median 9
Range 6
Mode 10, appeared 3 times
Geometric Mean 8.8206311297046
Largest 12
Smallest 6
Sum 99
Count 11
■ 1st quartile (lower quartile) = 7.5
■ 2st quartile (median) = 9
■ 3st quartile (upper quartile) = 10
Answer:
solution set of f(x) = g(x) is x∈{0,1}
Step-by-step explanation:
For all exponential functions b^x,
b^0 is always 1, and b^1 is always b.
f(x) = -3/4 x + 2
g(x) = (1/4)^x + 1
g(0) = 2, f(0) = 2
g(1) = 5/4, f(1) = 5/4
Step-by-step explanation:
<h3>
<em><u>Given</u></em><em><u>:</u></em></h3>
Length of the rectangle = 6.5 m
Width of the rectangule = 7.3 m
<h3>
<em><u>Then</u></em><em><u>:</u></em></h3>
<u>First</u><u> </u><u>case</u><u>,</u>
Area of the rectangle
= length × width
= 6.5 m × 7.3 m
= <em><u>47.45</u></em><em><u> </u></em><em><u>s</u></em><em><u>q</u></em><em><u>.</u></em><em><u>m</u></em><em><u> </u></em><em><u>(</u></em><em><u>Ans</u></em><em><u>)</u></em><em><u>(</u></em><em><u>i</u></em><em><u>)</u></em>
<u>Second</u><u> </u><u>case</u><u>,</u>
Perimeter of the rectangle
= 2(length + width)
= 2(6.5 + 7.3)m
= 2 × 13.8 m
= <em><u>27</u></em><em><u>.</u></em><em><u>6</u></em><em><u> </u></em><em><u>m</u></em><em><u> </u></em><em><u>(</u></em><em><u>Ans</u></em><em><u>)</u></em><em><u>(</u></em><em><u>ii</u></em><em><u>)</u></em>
Let a,b,c,d and e are five numbers
mean = (a +b+ c+ d+e)/5 = 30
⇒ (a +b+ c+ d+e) = 150_______(1)
now, Let the number excluded be a
then, new mean = (b+ c+ d+e)/4 = 28
⇒ (b+ c+ d+e)= 112
putting this value in (1),
⇒a + 112 = 150
⇒a = 150 -112 = 38
excluded number = 38
Answer:
it can hold 6000 cans
Step-by-step explanation:
brainliest plz
