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11Alexandr11 [23.1K]
3 years ago
15

Use the Remainder Theorem to determine which of the roots are roots of F(x). Show your work.

Mathematics
1 answer:
Brums [2.3K]3 years ago
3 0

Answer:    x1=1   x2=-2  and x3=2

Step-by-step explanation:

1st   x1=1 is 1 of the roots , so

F(1)=1-1-4+4=0 - true

So lets divide x^3-x^2-4x+4 by (x-x1), i.e  (x^3-x^2-4x+4) /(x-1)=(x^2-4)

x^2-4 can be factorized as (x-2)*(x+2)

So x^3-x^2-4x+4=(x-1)*(x^2-4)=(x-1)(x-2)*(x+2)

So there are 3 dofferent roots:

x1=1   x2=-2  and x3=2

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You really can’t simply it but if u use disruptive property it would be -x - -8
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Let E = {(x, y) e R2|xy > 0}. Determine whether E is a subspace of R2 . X3
gayaneshka [121]

Answer:

E is not a subspace of \mathbb{R}^2

Step-by-step explanation:

E is not a subspace of  \mathbb{R}^2

In order to see this, we must find two points (a,b), (c,d) in  E such that (a,b) + (c,d) is not in E.

Consider

(a,b) = (1,1)

(c,d) = (-1,-1)

It is easy to see that both (a,b) and (c,d) are in E since 1*1>0 and (1-)*(-1)>0.  

But (a,b) + (c,d) = (1-1, 1-1) = (0,0)

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5 0
3 years ago
Consider the function. f(x) = 2x(x - 1)<br> What are the values of<br> f(0)=<br> f(3)=<br> f(-4)=
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3

Step-by-step explanation:

7 0
3 years ago
Me pueden ayudar a resolver por método de sustitución porfa.<br><br> {5x+7y=-1<br><br> {-3x+4y=-24
disa [49]

Answer:

x = 4 and y = -3

Question;

Me pueden ayudar a resolver por método de sustitución porfa.

Translation: Can you help me to solve by please substitution method.

{5x+7y=-1

{-3x+4y=-24

Step-by-step explanation:

Given the simultaneous equation.

5x+7y=-1 .....1

-3x+4y=-24 .....2

From equation 2, making y the subject of formula.

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Substituting the equation 3 into equation 1

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y = (-24+12)/4

y = -12/4

y = -3

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3 years ago
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