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Yakvenalex [24]
3 years ago
9

A factory makes cars at a constant rate. The table shows the number of car’s made for different length’s of time. A manager draw

’s a graph of the number of car’s made per hour. What is the slope of the line?

Mathematics
2 answers:
blagie [28]3 years ago
8 0

Answer:

im not sure if this is right or not but i did the math and got 26

Step-by-step explanation:

azamat3 years ago
7 0

Answer: 26

Step-by-step explanation:

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Question 9: Please help, what would be the length of the image of the segment GH?
shepuryov [24]

Answer:

<u><em></em></u>

  • <u><em>The length of the image of the segment GH would be 5 units.</em></u>

Explanation:

You can use the <em>center of dilation</em> as your origin of coordintes.

Thus, the <em>point H</em> would have coordinates (0,0) and the <em>point G</em> (-1,0).

A <em>dilation</em> multiplies the coordinates by the <em>scale factor</em>. Hence:

  • H = (0,0) → H' = 5 × (0,0) = (0,0)
  • G = (-1,0) → G] = 5 × (-1, 0) = (-5, 0)

Thus, the length of the image of segment GH would be the distance from 0 to -5 in a number line, which is 5.

3 0
3 years ago
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Determine if the equation 4x^2 - 6y^2 = 144 represents an ellipse or a hyperbola, then determine if the ellipse or hyperbola is
PilotLPTM [1.2K]
It represents a horizontal hyperbole
8 0
3 years ago
Compute a · (b ✕ c), where a = i − 3j + k, b = 4i + j + k and c = 9i − j + 3k.
grandymaker [24]
\mathbf a=\mathbf i-3\,\mathbf j+\mathbf k
\mathbf b=4\,\mathbf i+\mathbf j+\mathbf k
\mathbf c=9\,\mathbf i-\mathbf j+3\,\mathbf k

\mathbf b\times\mathbf c=\begin{vmatrix}\mathbf i&\mathbf j&\mathbf k\\4&1&1\\9&-1&3\end{vmatrix}=4\,\mathbf i-3\,\mathbf j-13\,\mathbf k

\mathbf a\cdot(\mathbf b\times\mathbf c)=(\mathbf i-3\,\mathbf j+\mathbf k)\cdot(2\,\mathbf i-3\,\mathbf j-13\,\mathbf k)=4+(-3)^2-13=0
6 0
3 years ago
The equation shows the relationship between x and y:
aliina [53]
The pattern of a linear function, is the following:

y  = mx + b

Where m is always the slope.

m in this case is -4, hence

The correct answer for your question is -4.
8 0
3 years ago
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What are the focus and directrix of the parabola that is the graph of the function f(x)=x²?
Hitman42 [59]

Answer:

Step-by-step explanation:

Given

y=x^2

comparing it with standard equation x^2=4ay

so 4a=1

a=\frac{1}{4}

so Focus of parabola is (0,0)

directrix

y=-a

here a=\frac{1}{4}

y=-\frac{1}{4}      

5 0
3 years ago
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