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Yakvenalex [24]
3 years ago
9

A factory makes cars at a constant rate. The table shows the number of car’s made for different length’s of time. A manager draw

’s a graph of the number of car’s made per hour. What is the slope of the line?

Mathematics
2 answers:
blagie [28]3 years ago
8 0

Answer:

im not sure if this is right or not but i did the math and got 26

Step-by-step explanation:

azamat3 years ago
7 0

Answer: 26

Step-by-step explanation:

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How do i solve this problem
VMariaS [17]
The sum of the interior angles of a quadrilateral -(4 sided shape)
its 360 degrees

add up all the angles, set it equal to 360 degrees, solve for x

any questions
6 0
3 years ago
How do i simplify this?
Law Incorporation [45]

Answer:

k = 8

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

Step-by-step explanation:

<u>Step 1: Define</u>

-84 = -2(2 + 5k)

<u>Step 2: Solve for </u><em><u>k</u></em>

  1. Divide -2 on both sides:                    42 = 2 + 5k
  2. Isolate <em>k</em> term:                                    40 = 5k
  3. Isolate <em>k</em>:                                             8 = k
  4. Rewrite:                                              k = 8

<u>Step 3: Check</u>

<em>Plug in k into the original equation to verify it's a solution.</em>

  1. Substitute in <em>k</em>:                    -84 = -2(2 + 5(8))
  2. Multiply:                               -84 = -2(2 + 40)
  3. Add:                                     -84 = -2(42)
  4. Multiply:                               -84 = -84

Here we see that -84 does indeed equal -84.

∴ k = 8 is the solution to the equation.

5 0
3 years ago
The width of each of five continuous classes in a frequency distribution is 5 and the lower class-limit of the lowest class is 1
Helga [31]

Let x and y be the upper and lower class limit of frequency distribution.

Given, width of the class = 5

⇒ x-y= 5 …

Also, given lower class (y) = 10 On putting y = 10, we get

x – 10= 5 ⇒ x = 15 So, the upper class limit of the lowest class is 15

Hence, the upper class limit of the highest class

=(Number of continuous classes x Class width + Lower class limit of the lowest class)

= 5 x 5+10 = 25+10=35

Hence,’the upper class limit of the highest class is 35.

<em><u>Alternate Method</u></em><em><u>.</u></em>

After finding the upper class limit of the lowest class, the five continuous classes in a frequency distribution with width 5 are 10-15,15-20, 20-25, 25-30 and 30-35.

Thus, the highest class is 30-35..

<h3>Hence, the upper limit of this class is 35.</h3>

<h2>_____________________</h2>

4 0
3 years ago
A penny collection contains twelve 1967 pennies, seven 1868 pennies and eleven 1971 pennies. If you are to pick some pennies wit
algol [13]

Answer:

You must pick at least 13 pennies to be sure of getting at least five from the same year.

Step-by-step explanation:

You have:

12 1967 pennies

7 1868 pennies

11 1971 pennies.

how many must you pick to be sure of getting at least five pennies from the same year?

This value is the multiplication of the number of different pennies by the antecessor of the number of pennies you want, added by 1.

So

You have 3 differennt pennies

You want to get at least five from the same year.

3*4 + 1 = 13

You must pick at least 13 pennies to be sure of getting at least five from the same year.

For example, if you pick 12 pennies, you can have four from each year.

Adding three values, 13 is the smallest number that you need at least one term of the addition being equal or bigger than 5.

5 0
4 years ago
Help me fast!!!!!! I am in school and i need to finish this
Minchanka [31]

Answer:

10/7

Step-by-step explanation:

100/70=slope

divide by 5

20/14

10/7

7 0
3 years ago
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