Answer:
(3-2h)^3 + (3-2h)^4 = (3-2h^2)^3 (1 + (3-2h^2))
Answer:
x = 21°
y = 29°
Step-by-step explanation:
a) Solving for x
Note that:
(3x - 3)° and 60° are Alternate interior angles, and alternate interior angles are equal to each other, hence:
3x - 3 = 60° (Alternate interior angles)
Add 3 to both sides
3x - 3 +3 = 60 + 3
3x = 63°
x = 63°/3
x = 21°
b) Solving for y
Notes that:
(3x - 3)° and (4y + 4)° are Consecutive interior angles and the sum consecutive interior angles is 180°
3x - 3 + 4y + 4 = 180°
3x + 4y - 3 + 4 = 180°
3x + 4y + 1 = 180°
Note that x = 21
Hence
3(21) + 4y + 1 = 180°
63 + 1 + 4y = 180°
64 + 4y = 180°
Subtract 64 from both sides
64 - 64 + 4y = 180° - 64
4y = 116°
y = 116/4
y => 29°
English ⬇️
So, 8*8=64, and is expressed as 64 square feet. A square has all sides equal. So, since one side is 8 feet long the other sides also have the same length. Area of a rectangle is length multiplied by the width.
Answer?= 8
Spanish ⬇️
Entonces, 8 * 8 = 64, y se expresa como 64 pies cuadrados. Un cuadrado tiene todos los lados iguales. Entonces, dado que un lado mide 8 pies de largo, los otros lados también tienen la misma longitud. El área de un rectángulo es la longitud multiplicada por el ancho.
hola no puedo hablar español así que tuve que traducir espero que esto sea bueno y la respuesta es 8 ¡buena suerte!
Let 1993 = time 0 = 0.
Let 1999 = time 6 = 6
Let 2012 = time 19 = 19
So, a = 171 (million). First solve for k.
176 = 171 e^k6
176/171 = e^(k*6)
ln (176/171) = 6k
k = 1/6 ln (176/171)
So, in 2012 we have: P(19) = 171 e^(19k), where k = 1/6 ln (176/171)
Hope this helped!
Answer:
<h2>
<em><u>No </u></em><em><u>solution</u></em></h2>
Step by Step Solution
<em><u>STEP1:</u></em>
Solving a Single Variable Equation:
<h3> 1.1
<em><u>Solve -xb+3x+3 = 0</u></em></h3>
<em><u>In this type of equations, having more than one variable (unknown), you have to specify for which variable you want the equation solved.</u></em>
<em><u>In this type of equations, having more than one variable (unknown), you have to specify for which variable you want the equation solved.</u></em>
<em><u>No solutions found</u></em>
