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notka56 [123]
3 years ago
6

PLEASE HELP DUE SOON!!!!! type an equation for the following pattern

Mathematics
1 answer:
const2013 [10]3 years ago
4 0

Answer:

28?

Step-by-step explanation:

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The points in the table represent a linear function. What is the equation of the line?
Damm [24]

Answer:

7

Step-by-step explanation:

7 0
3 years ago
What is the range of f(x)=e^x?
Tanzania [10]
The range refers to the value of y for which x is define.

So let y=f(x),

y =  {e}^{x}

Try making x the subject to obtain,

x =  ln(y)
x is defined for all real values of y greater than
0.

Hence the correct answer is D.
8 0
3 years ago
Read 2 more answers
Tan9°. tan27°. tan45°. tan72°. tan81°= 1​<br><br>could u plz solve it with clear process
Inga [223]

<u>Correct</u><u> </u><u>question</u><u>:</u><u>-</u>

<u>Prove </u><u>that </u><u>tan9.</u><u>t</u><u>a</u><u>n</u><u>1</u><u>7</u><u>.</u><u>t</u><u>a</u><u>n</u><u>4</u><u>5</u><u>.</u><u>t</u><u>a</u><u>n</u><u>7</u><u>3</u><u>.</u><u>t</u><u>a</u><u>n</u><u>8</u><u>1</u><u>=</u><u>1</u>

<u>LHS</u>

\\ \sf\longmapsto tan9.tan17.tan45.tan73.tan81

\\ \sf\longmapsto tan9.tan81.tan17.tan73.tan45

\\ \sf\longmapsto tan(90-81).tan81.tan(90-73).tan73.1

\\ \sf\longmapsto cot81.tan81.cot73.tan73

\\ \sf\longmapsto 1.1

\\ \sf\longmapsto 1

5 0
2 years ago
Read 2 more answers
SHAWTY A LIL BXDDIE SHEE LIL MEHHH PUTANGGGG ;) MUHAHAH Imao
daser333 [38]

Answer:

i can agree with that muhahaha

Step-by-step explanation:

8 0
3 years ago
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An account has $26,000 after 15 years. The account received 2.3 percent interest compounded continuously. How much was deposited
Leya [2.2K]

The intital amount deposited was  $18485.82.

<h3>How to find the compound interest?</h3>

If n is the number of times the interested is compounded each year, and 'r' is the rate of compound interest annually, then the final amount after 't' years would be:

a = p(1 + \dfrac{r}{n})^{nt}

An account has $26,000 after 15 years. The account received 2.3 percent interest compounded continuously.

A = 26000

R = 0.02.3

a = p(1 + \dfrac{r}{n})^{nt}

26000 = p(1 + \dfrac{2.3}{100})^{15}\\\\26000 = p \times 1.4064\\\\\P= 18485.82

Therefore, the intital amount deposited was  $18485.82.

Learn more about compound interest here:

brainly.com/question/1329401

#SPJ1

7 0
2 years ago
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