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notka56 [123]
3 years ago
6

PLEASE HELP DUE SOON!!!!! type an equation for the following pattern

Mathematics
1 answer:
const2013 [10]3 years ago
4 0

Answer:

28?

Step-by-step explanation:

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Choose the correct numbers from the box below to complete the subtraction sentence that follows
maw [93]

Answer:

umm there isn't a subtraction sentence

Step-by-step explanation:

7 0
2 years ago
Find the differential coefficient of <br><img src="https://tex.z-dn.net/?f=e%5E%7B2x%7D%281%2BLnx%29" id="TexFormula1" title="e^
Gemiola [76]

Answer:

\rm \displaystyle y' =   2 {e}^{2x}   +    \frac{1}{x}  {e}^{2x}  + 2 \ln(x) {e}^{2x}

Step-by-step explanation:

we would like to figure out the differential coefficient of e^{2x}(1+\ln(x))

remember that,

the differential coefficient of a function y is what is now called its derivative y', therefore let,

\displaystyle y =  {e}^{2x}  \cdot (1 +   \ln(x) )

to do so distribute:

\displaystyle y =  {e}^{2x}  +   \ln(x)  \cdot  {e}^{2x}

take derivative in both sides which yields:

\displaystyle y' =  \frac{d}{dx} ( {e}^{2x}  +   \ln(x)  \cdot  {e}^{2x} )

by sum derivation rule we acquire:

\rm \displaystyle y' =  \frac{d}{dx}  {e}^{2x}  +  \frac{d}{dx}   \ln(x)  \cdot  {e}^{2x}

Part-A: differentiating $e^{2x}$

\displaystyle \frac{d}{dx}  {e}^{2x}

the rule of composite function derivation is given by:

\rm\displaystyle  \frac{d}{dx} f(g(x)) =  \frac{d}{dg} f(g(x)) \times  \frac{d}{dx} g(x)

so let g(x) [2x] be u and transform it:

\displaystyle \frac{d}{du}  {e}^{u}  \cdot \frac{d}{dx} 2x

differentiate:

\displaystyle   {e}^{u}  \cdot 2

substitute back:

\displaystyle    \boxed{2{e}^{2x}  }

Part-B: differentiating ln(x)•e^2x

Product rule of differentiating is given by:

\displaystyle  \frac{d}{dx} f(x) \cdot g(x) = f'(x)g(x) + f(x)g'(x)

let

  • f(x) \implies   \ln(x)
  • g(x) \implies    {e}^{2x}

substitute

\rm\displaystyle  \frac{d}{dx}  \ln(x)  \cdot  {e}^{2x}  =  \frac{d}{dx}( \ln(x) ) {e}^{2x}  +  \ln(x) \frac{d}{dx}  {e}^{2x}

differentiate:

\rm\displaystyle  \frac{d}{dx}  \ln(x)  \cdot  {e}^{2x}  =   \boxed{\frac{1}{x} {e}^{2x}  +  2\ln(x)  {e}^{2x} }

Final part:

substitute what we got:

\rm \displaystyle y' =   \boxed{2 {e}^{2x}   +    \frac{1}{x}  {e}^{2x}  + 2 \ln(x) {e}^{2x} }

and we're done!

6 0
3 years ago
In a well-shuffled, standard 52 card deck, what is the probability that a card is a Queen, given that it is a black card
dlinn [17]
There are two black queens in a standard deck, so the probability is 2/52 or 1/26.

If instead you know you pulled a black card from the deck and you’re wondering what the probably is that it’s a queen, then it’s 2/26, since there are still 2 black queens, but only 26 black cards.
7 0
3 years ago
Read 2 more answers
Expressions that simplify to the same expression are called ____ expressions.
7nadin3 [17]
They're equivalent expressions
4 0
3 years ago
Read 2 more answers
Zoe goes out to lunch. The bill
DanielleElmas [232]

Answer:

$60

Step-by-step explanation:

To find how much Zoe paid before the sales tax and tip, we first need to consider the amount she paid in sales tax and tips.

Sales tax  + Tips = $18.60

Let x = original price

Sales tax = 11% * original price

Sales tax = 0.11 * x

x= 0.11x

Tips = 20% * original price

Tips = 0.20 * x

x = 0.2x

Now that we have a value for both the sales tax and tips, we can then proceed to find the original price by:

0.11x + 0.2x = 18.60

0.31x = 18.60

Now we need to divide both sides by 0.31 to find x.

x = 60

Zoe's dinner before the sales tax and tips was $60.

5 0
3 years ago
Read 2 more answers
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