The answer is 4 diploid cells.
Meiosis is a cell division which results in the reduction of chromosome number by half - from diploid to haploid - in daughter cells. It consists of meiosis I and meiosis II. Meiosis I produces <em>two haploid cells</em>.<span> Meiosis II is analogous to mitosis, so in total, meiosis results in four haploid cells. This is achieved through suppression of DNA replication between two meiotic divisions.
If there were no </span><span>suppression of DNA replication, then meiosis I would produce <em>two diploid cells</em>, and after meiosis II there will be four diploid cells.</span>
Answer:
The mentioned parental types are c+m- and c-m+. Thus, the recombinants will be c+m+ and c-m-.
Now, the given distance between c and m is 8 map units. Thus, the recombinant frequency is 8% or 0.08.
The total recombinants from 1000 plaques will come out to be 80,
Thus, the recombinants of each type will be 40.
Total parental type will be 920, and therefore, each parental type count will be 460.
Thus, expected c+m- = 460, expected c-m+ = 460, expected c+m+ = 40 and expected c-m- = 40.
Answer: Option D
Explanation:
The bacteria can undergo cell differentiation in response to the environmental conditions.
The oxidative stress, antibiotic exposure, stress conditions are some of the external conditions due to which the bacterial cell can respond in the cell differentiation.
The bacterial species can divide based in the conditions in which they are put. So it is true that under stress conditions the bacterial cell can undergo cell differentiation.
the total number of pushes all together will be <u>8</u><u>N</u>
After a large meal, the pancreas helps by producing insulin, which helps break down sugars.
