Answer:
m = 0
Step-by-step explanation:
<u>If two lines are parallel, their slopes are equal. </u>
The slope of x - axis is 0
(why?)
because, slope of a line is given by

Θ is the angle made by the line with the x- axis.
Here, the line in question is the x- axis itself, and every line makes an angle of 0° with itself.
=> Θ = 0
=> tan Θ = 0
=> slope = 0
and the line in blue is parallel to the X- axis, therefore, it's slope is also 0
(also, a line makes an angle of 0° with the line it's parallel to)
<u> </u>

-2x + 5 < 7
-2x + 5 < 7
<u> -5 -5 </u> deduct 5 from both sides
-2x < 2
<u>÷ -2 ÷ -2 </u> divide both sides by negative 2. Because of the division
x > -1 using a negative number, the sign is then reversed.
from < it becomes >.
The value of x should be greater than -1. It can be 0, 1, 2, so on...
To check: Revert back to the original sign which is <.
x = 1
-2x + 5 < 7
-2(1) + 5 < 7
-2 + 5 < 7
3 < 7
Answer:
Step-by-step explanation:
Option C is the correct answer
Answer:
4
Step-by-step explanation:
The equation of the line is written in the slope-intercept form, which is: y = mx + b, where m represents the slope and b represents the y-intercept. In our equation, y = − 7 x + 4 , we see that the y-intercept of the line is 4.
Add me brainiest
Answer:
y = 5cos(πx/4) +11
Step-by-step explanation:
The radius is 5 ft, so that will be the multiplier of the trig function.
The car starts at the top of the wheel, so the appropriate trig function is cosine, which is 1 (its maximum value) when its argument is zero.
The period is 8 seconds, so the argument of the cosine function will be 2π(x/8) = πx/4. This changes by 2π when x changes by 8.
The centerline of the wheel is the sum of the minimum and the radius, so is 6+5 = 11 ft. This is the offset of the scaled cosine function.
Putting that all together, you get
... y = 5cos(π/4x) + 11
_____
The answer selections don't seem to consistently identify the argument of the trig function properly. We assume that π/4(x) means (πx/4), where this product is the argument of the trig function.